Answer:
x=9
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
12=x+3
Step 2: Flip the equation.
x+3=12
Step 3: Subtract 3 from both sides.
x+3−3=12−3
Answer:
x=6
Step-by-step explanation:
The inverse is the equation with the x and y variables transposed
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
bearing in mind that the an hour has 15 + 15 + 15 + 15 = 60 minutes, so 15 minutes in 1/4 of an hour, thus 45 minutes is 3/4 of an hour.
now, from 11PM, if we add the 5 hours first, we'll be at 4AM, pass midnight of course.
now let's add the minutes, 32 and then 45, that gives us 77 minutes.
so the time will be 4AM plus 77 minutes, since 60 minutes is 1 hr, so 4AM plus 1 hr and 17 minutes, that'd be 5:17AM.
