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1 year ago

10

66 points! for if you get this right 99 kids go race go karts for a all day pass is $56 per kid then they play arcade games at a

total of $555 how much total was spent?

1 answer:

Romashka-Z-Leto [24]1 year ago

7 0

The total amount that was spent is $6099

<h3>How to determine the total amount that was spent?</h3>

The given parameters are

Number of kids = 99

Pass = $56 per kid

Arcade game = $555

The total amount that was spent is calculated as

Total = Number of kids * Pass + Arcade game

So, we have

Total = 99 * 56 + 555

Evaluate the expression

Total = 6099

Hence, the total amount that was spent is $6099

Read more about expressions at

brainly.com/question/723406

#SPJ1

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Will mark brainlist and rate 5/5

erastova [34]

Sir you don’t even have a question

5 0

3 years ago

Please help lot of points at stake- and will give brainly.

Veronika [31]

Answer:

a)1400 + 300x ≤ 5000

b) x ≤ 12 days

Step-by-step explanation:

a) Since the grocery store owner wants to stay within budget then, this means he would be spending at most $5,000

The word at most is represented by the inequality sign ≤ = Less than or equal to

Let x = Number of days

Hence,

Our inequality equation is

$1400 + 300× x ≤ $5000

1400 + 300x ≤ 5000

b) Solving for x

1400 + 300x ≤ 5000

300x ≤ 5000 - 1400

300x ≤ 3600

x ≤ 3600/300

x ≤ 12 days

3 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

Segments AB, EF, and CD intersect at point C, and angle ACD is a right angle. Find the

Dominik [7]

G=37

Angle ACD and angle DCB are a linear pair. Meaning they are supplementary.

ACD=90 degrees

180-90=90

90 degrees equals the angle of DCB.

90-53=37

So g=37

3 0

3 years ago

Please help ASAP 25 pts + brainliest to right/best answer

zhuklara [117]

Answer:

Step-by-step explanation:

LOGb(x)=y

4^5=1024

= log(4)1024=5

4 0

4 years ago