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Ber [7]
2 years ago
5

45 + 54 = 99 times ( ) + ( )

Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0

a) You have to find the greatest common factor for the values 45 and 54

To do so you have to determine the factors for each value and determine the highest value both numbers are divisible for.

Factors of 45 are

1, 3, 5, 9, 15, 45

Factors of 54 are

1, 2, 3, 6, 9, 18, 27, 54

The greatest common factor is 9, this means that you can divide both numbers by 9 and the result will be an integer:

\frac{45}{9}=5\frac{54}{9}=6

b) Given the addition

45+54

You have to factorize the adition using the common factor.

That is to "take out" the 9 of the addition, i.e. divide 45 and 54 by 9 and you get the result (5+6) but for this result to be equvalent to the original calculation, you have to multiply it by 9

45+54=9(5+6)

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Need help with 19-20 your suppose to simplify the expression
lesya692 [45]

To solve problem 19, we must remember the order of operations. PEMDAS tells us that we should simplify numbers in parentheses first, exponents next, multiplication and division after that, and finally addition and subtraction. Using this knowledge, we can begin to simplify the problem by working out the innermost set of parentheses:

36 / [10 - (3-1)²]

36 / [10 - (2)²]

Next, we should still simplify what is inside the parentheses but continue to solve the exponents (the next letter in PEMDAS).

36/ (10-4)

After that, we should compute the subtraction that is inside the parentheses.

36/6

Finally, we can solve using division.

6

Now, we can move onto problem 20:

1/4(16d - 24)

To solve this problem, we need to use the distributive property, which allows us to distribute the coefficient of 1/4 through the parentheses by multiplying each term by 1/4.

1/4 (16d-24)

1/4(16d) - 1/4(24)

Next, we can simplify further by using multiplication.

4d - 6

Therefore, your answer to problem 19 is 6 and the answer to problem 20 is 4d -6.

Hope this helps!

3 0
3 years ago
NEED THIS ASAP GUYS PLEASE DONT HAVE ME WRONG
Murrr4er [49]

Answer:

its 12

Step-by-step explanation:

LCM of 3,4 and 6 is 12

3 0
3 years ago
How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
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