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faltersainse [42]
4 years ago
10

A new interstate highway is being built with a design speed of 120 km/h. For one of the horizontal curves, the radius (measured

to the innermost vehicle path) is tentatively planned as 300 m. The limiting value for coefficient of side friction at 120 km/h is 0.09. What rate of superelevation is required for this curve at the 120 km/h design speed
Physics
1 answer:
nikklg [1K]4 years ago
4 0

Answer:

28.79%

Explanation:

Given

Design Speed, V = 120km/h = 33.33m/s

Radius, R = 300m

Side Friction, Fs = 0.09

Gravitational Constant = 9.8m/s²

Using the following formula, we'll solve the required rate of superelevation.

e + Fs = V²/gR where e = rate

e = V²/gR - Fs

e = (33.33)²/(9.8 * 300) - 0.09

e = 0.287853367346938

e = 28.79%

Hence, the required rate of superelevation for the curve is calculated as 28.79%

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An enemy spaceship is moving toward your starfighter with a speed, as measured in your frame, of 0.400c. The enemy ship fires a
kvasek [131]

Answer:

0.859375c

31.03 seconds

Explanation:

v' = Velocity of my ship = 0.4 c

u = Velocity of rocket = 0.7 c

c = Speed of light = 3\times 10^8\ m/s

s = Distance between my ship and enemy ship = 8\times 10^6\ km

Relativistic addition of speed is given by

v=\dfrac{v'+u}{1+\dfrac{uv'}{c^2}}\\\Rightarrow v=\dfrac{0.7+0.4}{1+\dfrac{0.7c\times 0.4c}{c^2}}\\\Rightarrow v=0.859375\ c

The speed of the missile is 0.859375c

Time is given by

t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{8\times 10^9}{0.859375\times 3\times 10^8}\\\Rightarrow t=31.03\ s

It will take 31.03 seconds to reach me.

6 0
3 years ago
50POINTS PLEASE HELP SPACE QUESTION
leonid [27]
Regardless of the time of year, the northern and southern hemispheres always experience opposite seasons. This is because during summer or winter, one part of the planet is more directly exposed to the rays of the Sun than the other, and this exposure alternates as the Earth revolves in its orbit.
4 0
3 years ago
Read 2 more answers
A nonrelativistic electron is accelerated from rest through a potential difference. After acceleration the electron has a de Bro
aleksley [76]

Answer:

Potential difference though which the electron was accelerated is 2.67\times 10^{-6}\ uV\  .

Explanation:

Given :

De Broglie wavelength , \lambda=750\ nm.

Plank's constant , h=6.626\times 10^{-34}\ J.s \ .

Charge of electron , e=-1.6\times 10^{-19}\ C.

Mass of electron , m=9.11\times 10^{-31}\ kg.m=9.11\times 10^{-31}\ kg.

We know , according to de broglie equation :

\lambda=\dfrac{h}{mv}\\\\ v=\dfrac{h}{m\lambda}\\\\v=\dfrac{6.626\times 10^{-34}\ J.s \ }{9.11\times 10^{-31}\ kg\times 750\times 10^{-9}\ m }= 969.78\ m/s .

Now , we know potential energy applied on electron will be equal to its kinetic energy .

Therefore ,

qV=\dfrac{mv^2}{2}\\\\ V=\dfrac{mv^2}{2q}

Putting all values in above equation we get ,

V=2.67\times 10^{-6}\ uV .

Hence , this is the required solution.

5 0
3 years ago
Select the correct answer.
Nimfa-mama [501]

Answer:

This makes the products have less energy than the reactants that combined to produce them.

Explanation:

6 0
3 years ago
TRUE OR FALSE. When non-conservative forces are present, the amount of work done increases with the length of the path.
Ymorist [56]

Answer:

True

Explanation:

When non-conservative forces are present, the amount of work done increases with the length of the path, this is true because, when a force is applied, the force does when and the non-conservative forces also do work. Since the non-conservative force work against the force  applied, this tend to increase the net work done by the applied force to compensate for the loss in energy due to the work done by the non-conservative forces.

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