Answer:
50mph,60mph
Explanation:
Let speed of southbound train=x mph
Speed of northbound train,y=x+16 mph
Distance between two trains after 1.5 hour,174 miles.
We have to find the speed of two trains.
Distance=
Using the formula
You can analogize the photoelectric energy to
1 answer:
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Answer:
The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters
Explanation:
The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22. m/s
The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²
Therefore, we have the following suitable kinematic equation of motion;
v² = u² - 2 × a × s
Where;
v = The final velocity = 0 (The train comes to a stop)
s = The distance the train travels before coming to a stop
Substituting the values gives;
0² = 22.² - 2 × 0.5 × s
2 × 0.5 × s = 22.²
s = 22.²/1 = 493 67/81 m = 40/81 km
The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.
Answer:
= 4.86 s
= 1.98 s
Explanation:
<u><em>Given:</em></u>
Length = l = 1 m
Acceleration due to gravity of moon = = 1.67 m/s²
Acceleration due to gravity of Earth = = 10 m/s²
<u><em>Required:</em></u>
Time period = T = ?
<u><em>Formula:</em></u>
T = 2π
<u><em>Solution:</em></u>
<u>For moon</u>
<em>Putting the givens,</em>
T = 2(3.14)
T = 6.3
T = 6.3 × 0.77
T = 4.86 sec
<u>For Earth,</u>
<em>Putting the givens</em>
T = 2π
T = 2(3.14)
T = 6.3 × 0.32
T = 1.98 sec