The work done by the shopping basket is 147 J.
<h3>When is work said to be done?</h3>
Work is said to be done whenever a force moves an object through a certain distance.
The amount of work done on the shopping basket can be calculated using the formula below.
Formula:
Where:
- W = Amount of work done by the basket
- m = mass of the shopping basket
- h = height of the shopping basket
- g = acceleration due to gravity.
Form the question,
Given:
- m = 10 kg
- h = 1.5 m
- g = 9.8 m/s²
Substitute these values into equation 2
- W = 10(1.5)(9.8)
- W = 147 J.
Hence, The work done by the shopping basket is 147 J.
Learn more about work done here: brainly.com/question/18762601
Answer:
As frequency increases, wavelength decreases. Frequency and wavelength are inversely proportional. This basically means that when the wavelength is increased, the frequency decreases and vice versa.
Explanation:
Answer:
Accuracy measures how close results are to the true or known value. Precision, on the other hand, measures how close results are to one another.
Answer:
t = 1.15 + .713 = 1.863 [s]
Explanation:
To solve this problem we must use the following kinematic equation, but first we identify the initial data.
vo = 7 [m/s]
yo = 4 [m]
g = 9.81[m/s^2]
![v_{f}=v_{o}-g*t\\0 = 7 - (9.81*t)\\7 = 9.81*t\\t = 0.713[s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bo%7D-g%2At%5C%5C0%20%3D%207%20-%20%289.81%2At%29%5C%5C7%20%3D%209.81%2At%5C%5Ct%20%3D%200.713%5Bs%5D)
The final velocity happens at the moment when the maximum height is reached, at this point the final speed is zero.
![y=y_{o}+v_{o}*t-0.5*g*t^{2}\\ y = 0+ (7*0.713)-0.5*9.81*(0.713)^{2}\\ y = 2.5[m]](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2Bv_%7Bo%7D%2At-0.5%2Ag%2At%5E%7B2%7D%5C%5C%20y%20%3D%200%2B%20%287%2A0.713%29-0.5%2A9.81%2A%280.713%29%5E%7B2%7D%5C%5C%20y%20%3D%202.5%5Bm%5D)
The total elevation will be 2.5 + 4 = 6.5 [m]
Now using again the total height we can find the final velocity.
![v_{f}^2=v_{o}^2+2*g*y\\v_{f}=\sqrt{2*g*y}\\ v_{f}=\sqrt{2*9.81*6.5}\\ v_{f}=11.3[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%5E2%3Dv_%7Bo%7D%5E2%2B2%2Ag%2Ay%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%2Ag%2Ay%7D%5C%5C%20v_%7Bf%7D%3D%5Csqrt%7B2%2A9.81%2A6.5%7D%5C%5C%20v_%7Bf%7D%3D11.3%5Bm%2Fs%5D)
With this final velocity we cand find the time.
![v_{f}=v_{i}+g*t\\11.3=0+9.81*t\\11.3=9.81*t\\t=1.15[s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bi%7D%2Bg%2At%5C%5C11.3%3D0%2B9.81%2At%5C%5C11.3%3D9.81%2At%5C%5Ct%3D1.15%5Bs%5D)
Now we have to sum the two times, the time it takes to go up and the time it takes to go down.
t = 1.15 + .713 = 1.863 [s]