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Dmitry_Shevchenko [17]
3 years ago
15

What is the answer to 5+x=-9

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

5+x=-9

Use the subtractive property of equality to isolate x.

5+x=-9

-5 -5

x=-14

The value that satisfies x is -14. You can check your work by substituting x as -14 and checking if the equation is satisfied.

5+x=-9

x=-14

5+(-14)=-9

5-14=-9

-9=-9

the answer is correct. Succinctly, x=-14.

Alexus [3.1K]3 years ago
3 0
Subtract -9 by 5 and x should be -14.
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kramer

Answer:

p=12

Step-by-step explanation:

the expression 3(12+n) = 3(n+p) is equivalent only when p=12

5 0
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Pls Solve<br><br> find a. ga+q=r
prohojiy [21]

The value of a for the given equation is a=(r-q)/g.

The given equation is ga+q=r.

We need to find the value of a from the given equation.

<h3>What is an equation?</h3>

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Now, ga+q=r can be solved for a as follows:

⇒ga=r-q

⇒a=(r-q)/g

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To learn more about an equation visit:

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5 0
1 year ago
Evaluate the following expression: (-5)(6) + (-6) ÷ (-3). Remember to show your work
Vinil7 [7]

Answer:

-28

Step-by-step explanation:

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7 0
3 years ago
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What is the product of (4x+3)(-2x-5)
yuradex [85]
Use the FOIL method

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Combine like terms

-8x^2 -26x -15
8 0
4 years ago
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Which of the following ordered pairs are solutions to the system of equations below? y = 2x + 1 and y = 4x – 3 (1,4) (4,5) (2,5)
attashe74 [19]

Step-by-step explanation:

Hey there!

Given eqautions are:

y = 2x + 1......... (i)

y = 4x - 3...........(ii)

<em>Putting eqaution (ii) in eqaution (i), we get;</em>

4x - 3 = 2x + 1

<em>~ Keep like terms on same side.</em>

4x - 2x = 1+3

<em>~ Perform operations. ( +, -, *, /)</em>

2x = 4

x= 4/2

Therefore, X= 2.

<em>Putting the value of X in eqaution (i)</em>

y = 2x+1

y = 2*2+1

Therefore, y= 5.

Therefore, the ordered pair is (2,5).

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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