Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

The equations that can be used to determine the length of the room are:

y(y + 5) = 750

y²– 5y = 750

(y - 30) (y + 25) = 0

What are the equations?

A rectangle is a 2-dimensional object that has four sides and four right angles. A rectangle has two diagonals of equal length which bisect each other at right angles.

Area of a rectangle = length x width

• Length = y
• Width = y - 5

750 = y x (y - 5)

750 = y² - 5y

y² - 5y - 750 = 0

The factors of -750y² that add up to -5y are 25y and -30

(y² + 25y)(-30y - 750) = 0

y(y + 25) = 0

-30(y + 25) = 0

(y - 30) (y + 25) = 0.

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