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kvv77 [185]
1 year ago
9

the Andersons kept track of the time they spent watching television. Part A wich bar diagram represents the number of hours the

Andersons watched televisión on Friday and Saturday? Part B. How many hours did the Andersons watch televisión on Friday and Saturday? Part C find how many hours the Andersons watched in all. Drag and drop the correct number into each box. number may be used once, more than once. or not at all. Part D how many more hours did the Andersons watch televisión on Friday and Saturday than Wednesday and Thursday?

Mathematics
1 answer:
DENIUS [597]1 year ago
4 0

Part A:

Part B:

\begin{gathered} 4\frac{5}{6}=\frac{29}{6} \\ 3\frac{4}{6}=\frac{11}{3} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}=\frac{17}{2}=8\frac{3}{6} \end{gathered}

Part C:

\begin{gathered} 3\frac{1}{6}=\frac{19}{6} \\ 2\frac{3}{6}=\frac{15}{6} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}+\frac{19}{6}+\frac{15}{6}=\frac{85}{6}=14\frac{1}{6} \end{gathered}

Part D:

\frac{17}{2}-\frac{17}{3}=\frac{17}{6}=2\frac{5}{6}_{}

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A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.​
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Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

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a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

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S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , substitute values

S_{17} = \frac{17}{2} ( 2(- 8d) + 16d)

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The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?
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x=5+\frac{29}{z}-\frac{y}{z}

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Step-by-step explanation:

Given: (4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24

Let's move everything we can to the left side of the equation. Some things will cancel out.

5z^2+29z=xz^2+yz

Now, let's move the term that includes x to the left side of the equation. Everything else should be moved to the right.

-xz^2=-5z^2-29z+yz

Let's get rid of the negative sign in front of x by dividing both sides by -1.

xz^2=5z^2+29z-yz

To get x completely isolated, divide both sides by z^2.

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x=5+\frac{29}{z}-\frac{y}{z}

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

5z^2+29z=xz^2+yz

Now, let's move the term that includes y to the left side of the equation. Everything else should be moved to the right.

-yz=-5z^2-29z+xz^2

Again, let's get rid of the negative sign in front of the y by dividing both sides by -1.

yz=5z^2+29z-xz^2

To isolate y, divide both sides by z.

\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}

Simplify.

y=5z+29-xz

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