According to the reaction, when 355 ml of 1.65 m Hydrochloric acid solution are combined with too much aluminum, 26.03 g of aluminum chloride is created.
An inorganic substance with the formula AlCl3 is aluminum chloride, also referred to as aluminum trichloride. It takes the form of [Al(H2O)6] hexahydrate. Aluminum chloride is ALCl3, which is composed of six water molecules. Aqueous hydrochloric acid, also referred to as muriatic acid, is a type of hydrochloric acid. It is a colourless solution with an overpowering odor. Strong acid is how it is categorized.
2 Al(s) + 6 HCl is the given reaction. ———-> 2 AlCl3 + 3H2
Using the provided data
The amount of HCl in moles is n= Volume * Concentration = 0.58575 mol (1.65 M * 355 ml)/1000 ml
based on the response,
It takes 6 mols of HCl. To neutralize 2 moles of aluminum, 0.58575 mol of hydrochloric acid must be used.
using the cross-multiplication method, 0.19525 moles are obtained by multiplying 0.58575% by 2/ 6.
Weight of the AlCl3 = 0.1952 moles * 133.340538 g/mol = 26.03 g
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