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allochka39001 [22]

2 years ago

9

Investigator Nixon is asked to pick up a firearm at a crime scene. What is the correct way for Investigator Nixon to pick up the

firearm?
By the barrel
By the trigger
By the trigger guard
Any way is fine.

1 answer:

artcher [175]2 years ago

7 0

Answer:

i dont know

Explanation:

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Fluoride is moderately basic, by far the most basic of the halides. It is a terrible leaving group. Fluoride is many orders of m

TEA [102]

Answer: Bromide is many orders of magnitude better than fluoride in leaving group ability

Explanation:

As Size of an atom Increases, the Basicity Decreases this is because if we move downwards from the top of the periodic table to the bottom of the periodic table, the size of an atom increases. As size increases, basicity will decrease, meaning the element will be less likely to act as a base implying that the element will be less likely to share its electrons.

in the same vein. With an increase in size, basicity decreases, making the ability of the leaving group to leave increase to increase . This can be seen in the halogens going down the group from

F--- worst

Cl----fair

Br ----good

I-----excellent

with fluorine having the worst ability to leave than Bromine which is better in terms of the leaving group ability.

3 0

2 years ago

The reaction of Pb+4 and O-2 produces the compound of

vovikov84 [41]

Answer:

Pb₂O₄

Explanation:

The given species are:

Pb⁴⁺ O²⁻

Now, to solve this problem, we use the combining powers which corresponds to the number of electrons usually lost or gained or shared by atoms during the course of a chemical combination.

Pb⁴⁺ O²⁻

Combining power 4 2

Exchange of valencies 2 4

Now the molecular formula is Pb₂O₄

4 0

2 years ago

At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force,

lora16 [44]

Answer:

I don't know the ans please search on the Google you will get

And don't forget to mark me as brainlest please guys and follow me back please please please please please

And I will help you tooooooooooooooooo and follow u back if you follow me

7 0

2 years ago

Read 2 more answers

What is the missing word. Please Help Me. Thank you!!

Gnoma [55]

Calcium Floride (Caf2)
Hope this helped =D

7 0

2 years ago

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Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

3 years ago