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Lena [83]
3 years ago
10

How many grams are in 2.3 x 10^-4 moles of Ca3(PO4)2

Chemistry
1 answer:
OLEGan [10]3 years ago
3 0
Molar mass 

Ca₃(PO₄)₂ = 310 g/mol

1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?

m = 2.3x10⁻⁴ * 310 / 1

m = 0.0713 g 

hope this helps!
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Answer:

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Explanation:

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Answer:

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Explanation:

Given data:

Number of molecules of C₂H₆ = 4.88×10²⁵

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2C₂H₆  + 7O₂     →      4CO₂ + 6H₂O

Number of moles of C₂H₆:

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                     C₂H₆          :             CO₂

                          2           :               4

                           81         :           4/2×81 = 162 mol

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