We can use the ideal gas law equation to find the pressure PV = nRTwhere P - pressure V - volume - 2.6 x 10⁻³ m³ n - number of moles - 0.44 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature - 25 °C + 273 = 298 K substituting the values into the equation, P x 2.6 x 10⁻³ m³ = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K P = 419 281.41 Pa 101 325 Pa is equivalent to 1 atm Therefore 419 281.41 Pa - 1/ 101 325 x 419 281.41 = 4.13 atm Pressure is 4.13 atm
