Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
![(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2](https://tex.z-dn.net/?f=%28x-%28a%2Bbi%29%29%2A%28x-%28a-bi%29%29%3D%5C%5C%28x-a-bi%29%2A%28x-a%2Bbi%29%3D%5C%5C%28%5Bx-a%5D-bi%29%2A%28%5Bx-a%5D%2Bbi%29%3D%5C%5C%28x-a%29%5E2-%28bi%29%5E2%3D%5C%5C%28x-a%29%5E2-b%5E2%28-1%29%3D%5C%5C%28x-a%29%5E2%2Bb%5E2)
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Y=7 is just a straight horizonal line that is perpendicular to the y axis at 7
and y=1/2x+6, is in y=mx+b form where m=slope and b=yintercept so
to find the intersection, yo just find when both sentances are correct so
y=7
subsitute that into y=1/2x+6
7=1/2x+6
subtract 6 from both sides
1=1/2x
multiply both sides by 2
2=x
so the point (2,7) is the intersection
Answer:
<h2>x = -17</h2>
Step-by-step explanation:
There would be 2034 students competing in 2012.
We can write a simple equation to find this answer. Let X, be the number of students starting in 2012. Then, we multiply by 0.9 and 1.1 to get to 2014. To work backwards, just divide by 1.1, then by 0.9.
2014 / 1.1 / 0.9 = 2034
Answer: 12.1 ft
Step-by-step explanation:
A ramp represents a right-angled triangle so Pythagorean formula can be used to find the diagonal length which will also be the hypotenuse.
c² = a² + b²
Where:
c = hypotenuse
a = base
b = Height
c² = 11² + 5²
c² = 121 + 25
c² = 146
c = √146
c = 12.1 ft
