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Xelga [282]
1 year ago
10

Harry downloads album A which has 11 tracks.

Mathematics
1 answer:
Airida [17]1 year ago
6 0

Part a: Cost of downloading album B = 13.3 euros

Part b: Cost of downloading album B = 12.6 euros

Number of tracks in album A = 11 tracks

The total cost of downloading album A = 10.45 euro

Cost of each track on album A = Total cost of album/Number of tracks in the album

= 10.45/11

= 0.95 euro

Part a:

Number of tracks in album B = 14 tracks

Cost of album B = Number of tracks in album B * Cost of each track

= 0.95*14

= 13.3 euros

Part b:

The cost of 5 tracks on album B is 5p less therefore, the cost of 5 tracks will be 0.90*5 = 3.60 euros

The cost of 9 tracks on album B is 5p more therefore, the cost of 9 tracks will be = 1*9 = 9 euros

The total cost of downloading album B = 9+3.6 = 12.6 euros

Learn more about arithmetic:

brainly.com/question/22260035

#SPJ9

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What where William total fixed variable expenses the first year of college
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8 0
1 year ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

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Answer:

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Step-by-step explanation:

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