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GrogVix [38]
1 year ago
10

Suggest why some metals will react with hot water but not with cold water. Explain with one example. Draw figure.

Chemistry
1 answer:
Lelechka [254]1 year ago
5 0

The difference in the reactivity of metals accounts for why some metals will react with hot water but not with cold water. For example, aluminum is less reactive than sodium and will only react with hot water but not cold water.

<h3>What is reactivity of metals?</h3>

The reactivity of metals is the ability of a metals to lose electrons.

The reactivity of metals generally decreases from left to right across the periodic table but increases on going down a group.

Due to the differences in reactivity of metals, some metals are more reactive than others.

For example, the reactive metals sodium, potassium and calcium react with cold water to with differing degree of spontaneity to liberate hydrogen.

Some other metal like aluminum, zinc, and  iron can only react with hot water or steam to liberate hydrogen.

Therefore, the reactivity of a metal will determine if it will react with cold water or hot water.

Learn more about reactivity of metals at: brainly.com/question/28107797

#SPJ1

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What is the basic principle that is used during the during the structures of compounds​
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3 years ago
How does the structure of compounds determine the properties of the compounds?
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All of these properties are due to the chemical structure of the compound. The chemical structure includes the bonding angle, the type of bonds, the size of the molecule, and the interactions between molecules. Slight changes in the chemical structure can drastically affect the properties of the compound.

Explanation:

Hope it helps.

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2 years ago
A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
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Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

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