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3 years ago

17. What is the molarity of ZnCl2 that forms when 15 grams of Zn reacts completely with CuCl, if a

Chemistry

1 answer:

GalinKa [24]3 years ago

7 0

Answer:

1.31M

Explanation:

Based on the reaction, 1 mole of Zn produce 1 mole of ZnCl₂. As the reaction occurs completely, the moles of Zn added = Moles of ZnCl₂ produced. To find molarity we need the moles of ZnCl₂ and the volume of the solution in liters:

<em>Moles Zn = Moles ZnCl₂ -Molar mass Zn: 65.38g/mol-:</em>

15g * (1mol / 65.38g) = 0.23 moles of ZnCl₂

<em>Volume in Liters:</em>

175mL * (1L / 1000mL) = 0.175L

The molarity is:

0.23moles / 0.175L

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Describe in general terms the structure of ionic solids such as nacl

allochka39001 [22]

<span>Ionic compounds are chemical compounds in which ions are held together in a lattice structure by ionic bonds. They have a high melting and boiling point, and they have a high hardness and are very brittle. The cations and anions are stuck together in a sense. So in this case, sodium (Na) is attracted to Chlorine (Cl).</span>

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3 years ago

Could a mixture be made up of only one element and no compounds

Firdavs [7]

Yes. A mixture can be made up of just elements without the use of a compound, you can also just use compounds in a mixture without any elements

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3 years ago

Help?

Ahat [919]

Answer:

$KClO_3$

Explanation:

Hello!

In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:

$m_O=22.9g-7.33g-6.65g=8.92g$

Next, we compute the moles of each element:

$n_K=\frac{7.33g}{39.9g/mol}= 0.184mol\\\\n_{Cl}=\frac{6.65g}{35.45g/mol}=0.188mol \\\\n_O=\frac{8.92g}{16.00g/mol} =0.5575mol$

Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:

$K=\frac{0.184}{0.184}=1.0 \\\\Cl=\frac{0.187}{0.184}=1.0\\\\O=\frac{0.5575}{0.184} =3.0$

Therefore, the empirical formula is:

$KClO_3$

Regards!

3 0

2 years ago

AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the origin

svet-max [94.6K]

We have that the original pressure of this gas is mathematically given as

P2=17.854 kPa

<h3>Boyle's law</h3>

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law is mathematically given as

P1V1=P2V2

Therefore

$P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}$

P2=17.854 kPa

For more information on Pressure visit

brainly.com/question/25688500

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2 years ago

Which two changes would make this reaction favor the formation of products? 2502 +02= 2503 + energy A. Raising the temperature B

Alisiya [41]

C. Decreasing the temperature

D. Raising the pressure

<h3>Further explanation</h3>

Given

Reaction

2SO₂+O₂⇔2SO₃+energy

Required

Changes to the formation of products

Solution

The formation of SO₃ is an exothermic reaction (releases heat)

If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)

While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient

in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2

As the temperature decreases, the equilibrium will shift towards the exothermic reaction, so the reaction shifts to the right towards SO₃( products-favored)

And increasing the pressure, then the reaction shifts to the right SO₃( products-favored)⇒the number of coefficients is greater

4 0

3 years ago

Read 2 more answers