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lesantik [10]
3 years ago
13

Microwave ovens work by irradiating food with microwaves, which are absorbed by the water molecules in the food and converted to

heat. Assuming that microwave ovens emit radiation with a wavelength of 29.7 cm, calculate how many photons are emitted per second in a 600-Watt microwave oven. (1 W = 1 J/s)
Chemistry
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

8.969×10²⁶ photons

Explanation:

From the question,

Using,

E = hc/λ........................... Equation 1

Where E = Energy of the photon, h = Planck's constant, c = speed of light, λ = wave length of the photon.

Given: h =  6.626×10⁻³⁴ J.s, c = 3×10⁸ m/s, λ = 0.297 m

Substitute into equation 1

E = 6.626×10⁻³⁴(3×10⁸)/0.297

E = 6.69×10⁻²⁵ J.

The energy of the photon in one seconds = 6.69×10⁻²⁵ J/s

If the power of the microwave oven  = 600 J/s

Then,

Number of photons emitted per seconds = 600/(6.69×10⁻²⁵)

Number of photons emitted per seconds = 8.969×10²⁶ photons

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A pot of boiling water on the stove is slowly releasing steam. Which process is this an example of?
Viktor [21]

evaporation. When a substance undergoes a change of matter from a solid to gas, it is the process of evaporation.

Hope this helps

8 0
3 years ago
How Many Atoms Are In 356.13 Grams Of Sn
s344n2d4d5 [400]

<span>There are three atoms of Sn (Stannous or Tin) in</span> 356.13 g of Sn.

<span>One atom of Sn has the atomic mass (m</span>ₐ<span>) of </span>118,71u which means:

356.13/118.71=3 atoms of Sn

The mass number (symbol A) also called atomic mass number or nucleon number is the total number of protons and neutrons in an atomic nucleus. It determines the atomic mass of atoms and it is in the periodic table.

8 0
3 years ago
The partial pressure of CO2 gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO2 gas (in g) will be released f
frutty [35]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 4.60 atm = 7.59 \times 10^{-3} M

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

\frac{7.59 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.367 g

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 1.28 atm = 2.11 \times 10^{-3} M

\frac{2.11 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.102 g

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

m = 0.367 g - 0.102 g = 0.265 g

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: brainly.com/question/18987224

<em>The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.</em>

5 0
3 years ago
A buret was improperly read to 1 decimal place giving a reading of 27.2 mL. If the actual volume is 27.26 mL, what is the percen
Nezavi [6.7K]
Percent error can be calculated by the difference of the theoretical value and the measured value divided by the theoretical value multiplied by 100 percent. 

% error = 27.26 - 27.2 / 27.26 x100
% error = 0.22%

A value close to zero would mean that the measured value is more or less near the actual value.
5 0
3 years ago
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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 J electrical energy is
Alchen [17]

B) It was transformed into 350 J of heat energy.

Explanation:

The remaining 350J of energy must have been transformed into 350J of heat energy.

A fan works by converting electrical energy into heat energy.

  • According to the third law of thermodynamics "no system is 100% efficient". The conversion of the energy from one form to another involves a lost in energy.
  • Heat is one very familiar way by which energy can be lost.
  • Some component energy is used to heat the fan in the process and it is a wasted energy.
  • Friction surfaces a heat energy in this process.

learn more:

Third law of thermodynamics brainly.com/question/3564634

#learnwithBrainly

6 0
4 years ago
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