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lutik1710 [3]
1 year ago
6

A new baby is born in France the newspaper reports the baby's mass to be 1.5×10³ kg

Mathematics
1 answer:
Ira Lisetskai [31]1 year ago
4 0

The question only supplied us with the mass of the new baby which is:

1.5\cdot10^3\operatorname{kg}\Rightarrow1500\operatorname{kg}

This mass is too bizzarre & unrealistic for

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A tank has the shape of an inverted circular cone (point at the bottom) with height 10 feet and radius 4 feet. The tank is full
german

Answer:

Step-by-step explanation:

Given that tank has the shape of inverted circular cone

Height = 10 feet and radius =  4 feet

After water pumped out height = 5 ft

Hence volume of water pumped out = \frac{1}{3} \pi R^2 h-\frac{1}{3} \pi r^2 h'

Here we have r/h is constant always

Hence \frac{r}{h'} =\frac{R}{h} \\r=Rh'/h = 4(5)/10 = 2

Substitute to get volume of water pumped out = \frac{1}{3} \pi (10*16-4*5)=\frac{140\pi}{3}

Mass of water = density x volume = 62.4(\frac{140\pi}{3})\\= 2912\pi lbs

Work done = force x displacement

= mass x accen x displacement

Here acceleration = gravity = 32.2 ft/sec^2

Displaement = height reduced = 5 ft

W=2912(32.2)(5)\pi =468832\pi foot -pound

6 0
3 years ago
150 - 1/2s = 120 + 1/4s
agasfer [191]

Answer:

s=40

Step-by-step explanation:

Combine s and 1/2.

150−s/2=120+1/4s

Combine 1/4and s.

150−s/2=120+s/4

Move all terms containing s to the left side of the equation.

150−3s/4=120

Move all terms not containing s to the right side of the equation.

−3s/4=−30

Multiply both sides of the equation by −4/3.

−4/3 x (−3s/4)=−4/3 x−30 => S=40

3 0
3 years ago
Read 2 more answers
What is the value of (1/4) 2
notsponge [240]

Answer:

1/2 or 0.5

Step-by-step explanation:

Multiply 1/4 by 2/1

2/4

Simplify

1/2

Hope this helped :)

3 0
3 years ago
Read 2 more answers
Jami is trying to model the movement of a tire. In order to properly model the movement, she is going to focus on the movement o
USPshnik [31]

From the given data it is clear that the amplitude of the wave will be 9 inches.

It is also clear that the speed of rotation, ω, will be: \omega=\frac{2\pi}{T}=\frac{2\pi}{8}=\frac{\pi}{4}

Now, it is given that the nozzle is on the right side of the tire and that position is going to be treated as the equilibrium position, the tire is then rotated such that the nozzle goes up at the beginning of the rotation. This condition is possible only when we have a Sine (Sin) function.

Thus, our final answer can be arrived as:

Amplitude\times Sin(\omega t)

9\times sin(\frac{\pi}{4}t) =9sin(\frac{\pi}{4}t)

Thus, out of the given options, option B is the correct answer.


5 0
3 years ago
Is 11/128 equal to a terminating decimal or a repeating decimal ? Explain how you know
Ostrovityanka [42]

We need to determine whether \frac{11}{128} is a terminating decimal or a repeating decimal.

Let's solve this question using the long division method

First, let's identify the divisor and dividend. The number to be divided is 11 hence this is the dividend, and it needs to be divided by 128 which is the divisor

Next, since the divisor (128) is greater than the dividend (11) it can not divide 11. Hence, we will introduce a decimal point in quotient, and append a 0 next to 11 and divide 110 by 128. Again, 128 is greater than 110 so we will introduce a 0 in the quotient, and append another 0 next to 110, and will divide 1100 by 128. We will see what multiple of 128 is less than or equal to 1100. That multiple is 8. So we write 8 in the quotient and multiply 128 with 8 and subtract the product (128*8 = 1024) from 1100. The remainder that we get is 76.

Next, we append a 0 to the remainder and divide 760 by 128. Now, we see what multiple of 128 is less than or equal to 760. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 760. Now, the remainder is 120.

Next, we append a 0 to the remainder and divide 1200 by 128. Now, we see what multiple of 128 is less than or equal to 1200. That multiple is 9. So we write 9 next to the quotient and multiply 128 with 9 and subtract the product (1152) from 1200. Now, the remainder is 48.

Next, we append a 0 to the remainder and divide 480 by 128. Now, we see what multiple of 128 is less than or equal to 480. That multiple is 3. So we write 3 next to the quotient and multiply 128 with 3 and subtract the product (384) from 480. Now, the remainder is 96.

Next, we append a 0 to the remainder and divide 960 by 128. Now, we see what multiple of 128 is less than or equal to 960. That multiple is 7. So we write 7 next to the quotient and multiply 128 with 7 and subtract the product (896) from 960. Now, the remainder is 64.

Next, we append a 0 to the remainder and divide 640 by 128. Now, we see what multiple of 128 is less than or equal to 640. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 640. Now, the remainder is 0.

Hence, we have solved the entire problem

Last, we look at the quotient i.e. 0.0859375, which is the solution to the problem. We see that the quotient has a definite number of digits in it, and terminates at 5. Hence, this is a terminating decimal.

A repeating decimal is one in which a particular pattern after the decimal point keeps re-occuring, which is not the case here. Hence, \frac{11}{128} is a terminating decimal.

Please refer to the attached image for visualization

3 0
3 years ago
Read 2 more answers
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