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lutik1710 [3]
1 year ago
6

A new baby is born in France the newspaper reports the baby's mass to be 1.5×10³ kg

Mathematics
1 answer:
Ira Lisetskai [31]1 year ago
4 0

The question only supplied us with the mass of the new baby which is:

1.5\cdot10^3\operatorname{kg}\Rightarrow1500\operatorname{kg}

This mass is too bizzarre & unrealistic for

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If AB = 12 and CB = 10, then the height of the triangle is:
Ierofanga [76]
AD = DB = AB/2 = 6
cd = \sqrt{{bc}^{2} - {db}^{2} } \\ cd = \sqrt{64} \\ cd = 8
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3 years ago
To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meter
Sidana [21]
Technically, none of the equations.

The equation you're looking for would be:

x²+(x+20)²=150²


7 0
3 years ago
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A fish tackle box is 13 inches long, 6inches wide, and 2 1/2 inches high. What is the volume of the tackle box
Vika [28.1K]
V=lwh
13in × 6in × 2.5in = 195 in³
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3 years ago
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Q and r are independent events. if p(q) = 1/4 and p(r)=1/5, find p(q and r)
klasskru [66]

Answer:

(b) \frac{7}{30}

Step-by-step explanation:

When two p and q events are independent then, by definition:

P (p and q) = P (p) * P (q)

Then, if q and r are independent events then:

P(q and r) = P(q)*P(r) = 1/4*1/5

P(q and r) = 1/20

P(q and r) = 0.05


In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.


In the first ballot box there are 9 balls, 3 white and 6 yellow.

Then the probability of obtaining a white ball from the first ballot box is:

P (W_{u_1}) = \frac{3}{9} = \frac{1}{3}

In the second ballot box there are 10 balls, 7 white and 3 yellow.

Then the probability of obtaining a white ball from the second ballot box is:

P (W_{u_2}) = \frac{7}{10}

We want to know the probability of obtaining a white ball in both urns. This is: P(W_{u_1} and W_{u_2})  

As the events are independent:

P(W_{u_1} and W_{u_2})  = P (W_{u_1}) * P (W_{u_2})

P(W_{u_1} and W_{u_2})  = \frac{1}{3}* \frac{7}{10}

P(W_{u_1} and W_{u_2})  = \frac{7}{30}

Finally the correct option is (b) \frac{7}{30}

3 0
3 years ago
Choose the product. -6p3(3p2 + 5p - 1) -18p5 - 30p4 + 6p3 -18p6 - 30p3 - 6p 18p3 + 6p2 - 30p4 -18p6 - 24p3
wlad13 [49]
-6p^3(3p^2 +5p -1) = -18p^5 -30p^4 +6p^3

so this is the right answer sure 
7 0
3 years ago
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