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Evgen [1.6K]
1 year ago
8

100 POINTS AND BRAINLIST

Mathematics
2 answers:
Lesechka [4]1 year ago
8 0

Answer:

\sf tan(X) = 2.14

\sf sin(X)= 0.91

\sf cos(X)= 0.42

Solve for tan(X):

\sf tan(x) = \dfrac{opposite}{adjacent}

\sf tan(X) = \dfrac{30.8}{14.4}

\sf tan(X) = 2.14

Solve for sin(X):

\sf sin(x)= \dfrac{opposite}{hypotensue}

\sf sin(X)= \dfrac{30.8}{34}

\sf sin(X)= 0.91

Solve for cos(X):

\sf cos(x)= \dfrac{adjacent}{hypotensue}

\sf cos(X)= \dfrac{14.4}{34}

\sf cos(X)= 0.42

Alla [95]1 year ago
3 0
  • X=B

All ratios remains same

\\ \rm\hookrightarrow sinX=\dfrac{P}{H}=\dfrac{30.8}{34}=0.9

\\ \rm\hookrightarrow cosX=\dfrac{B}{H}=\dfrac{14.4}{34.4}=0.42

\\ \rm\hookrightarrow tanX=\dfrac{sinX}{cosX}=\dfrac{0.9}{0.42}=2.14

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kenny6666 [7]

Answer:

<em>9</em><em>0</em><em> </em><em>degree</em><em> </em><em>EFC</em><em>. </em><em>and</em><em>. </em><em>BMC</em>

<em>across</em><em> </em><em>fc</em><em>/</em><em>ma</em><em> </em>

<em>across</em><em> </em><em>ec</em><em>/</em><em>ab</em>

5 0
3 years ago
In parallelogram crhs, the measure of angle c is 48.Find the measure of angle h?
Lisa [10]

Answer:

48°

Step-by-step explanation:

we know that opposite angle of parallelogram is equal

so,

angel C is equal to opposite angle H

H = 48

angle C = 48°

angle R = 132°

angle H = 48° (opposite of angle C)

angle S = 132°(opposite of angle R)

Mark me Brainiest please

8 0
2 years ago
This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Plz help asap.. I have no clue how to do this.
ANTONII [103]

Answer:

Tn=a + (n-1)d

a= first term = 14

n= This is the term you're looking for... In this case... That's the 73rd term

d=Common difference (since its an AP)

d= second term - first term -- Or 3rd term - 2nd term = 23-14

d=9

T = 14 + (73-1)9

T= 14 + (72)9

T= 14 + 648

T=662.

4 0
3 years ago
Read 2 more answers
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