No photo?? what are the choices
Answer:
It doesn't.
Step-by-step explanation:
If you plug in 6 in the x spots you will have:
<h3>4(6)-5 < 19</h3>
If you solve that, you will get:
<h3>19< 19</h3>
So considering that they are the same number, this doesn't make sense because it should be an equal sign.
Have a nice day!!! Please mark Brainliest!
Answer:
4989600 ways
Step-by-step explanation:
From the question,
The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)
⇒ n!/(r₁!r₂!r₃!) ways
Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.
Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2
Substitute these value into the expression above
11!/(2!2!2!) = (39916800/8) ways
4989600 ways
Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways
The cost would be $4.74. 3.95 times 0.2 is 0.79. Add that to 3.95 and get 4.47
(A) Just because every digit has an equal chance of appearing does not mean that all will be equally represented. (See "gambler's fallacy")
(B) The experimental procedure isn't exactly clear, so assuming a table of digits refers to a table of just one-digit numbers, each with 0.1 chance of appearing (which means you can think of the digits 0-9), you should expect any given digit to appear about 0.1 or 10% of the time.
So if a table consists of 1000 digits, one could expect 7 to appear in 10% of the table, or about 100 times.