For this case a parameter represent the population data and for this case the parameter would be the true mean $\mu$ who represent the amount of gasoline they used in the previous week

$\bar X= \frac{\sum_{i=1}^n X_i}{3800} =11.75$

And the sample mean is an unbiased estimator of the true mean.

Step-by-step explanation:

For this case a parameter represent the population data and for this case the parameter would be the true mean $\mu$ who represent the amount of gasoline they used in the previous week

And in order to estimate the parameter of interest we use a survey of n =3800 and the sample mean who represent an statistic is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we got:

$\bar X= \frac{\sum_{i=1}^n X_i}{3800} =11.75$

And the sample mean is an unbiased estimator of the true mean.

4 0

2 years ago

Multiply & Simplify.

kipiarov [429]

<span>2a(7a²-3a+9)
=14a^3 - 6a^2 +18a

answer is </span><span>D. 14a³-6a²+18a</span>

3 0

2 years ago

Mary rode her bike for 2 2/5 miles on Wednesday. On Thursday, she biked 1 1/4 times as far as on Wednesday. How many miles did M

snow_lady [41]

2 2/5=12/5
1 1/4=5/4
12*5=60
5*4=20
60/20=3
So the answer is 3 miles

8 0

2 years ago