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rewona [7]
1 year ago
7

Automobile airbags contain solid sodium azide, nan3, that reacts to produce nitrogen gas when heated, thus inflating the bag.

Chemistry
1 answer:
forsale [732]1 year ago
5 0

The values of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C. The work done is -919 J.

The equation of the reaction is;

2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g )

Number of moles of NaN3 = 16.5 g/65 g/mol = 0.25 moles

If 2 moles of NaNa3 yields 3 moles of N2

0.25 moles of NaN3 yields  0.25 moles × 3 moles/2 moles

= 0.375 moles of N2

We need to find the volume change using the;

PV = nRT

P = 1.00 atm

V =?

n =  0.375 moles of N2

R = 0.082 atmLK-1mol-1

T =  22 ∘ C + 273 = 295 K

V = nRT/P

V = 0.375 × 0.082  × 295/ 1.00

V = 9.07 L

Recall that during expansion the gas does work. Work done by the gas is;

W = -PΔV

W =-( 1 atm × 9.07 L)

W = -9 Atm

Again;

1 L atm = 101.325 J

So,

-9 atmL =  -9 atmL × 101.325 J/1 L atm

= -919 J

The work done is -919 J.

Learn more about work done here:-brainly.com/question/25573309

#SPJ4

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Automobile airbags contain solid sodium azide, NaN 3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g ) Calculate the value of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C.

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There are two moles of benzene involved in the process (C6H6). Since the heat of this reaction is -6278 kJ, the burning of 2 moles of benzene will result in a heat loss of 6278 kJ. This reaction is exothermic.

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