Answer:
Oxygen is limiting reactant
Explanation:
2 H2 + O2 ======> 2 H2 O
from this equation (and periodic table) you can see that
4 gm of H combine with 32 gm O2
H / O = 4/32 = 1/8
32 /16 = 2/1 shows O is limiter
for 32 gm H you will need 256 gm O and you only have 16 gm
C = pK
<span>C = 4.4E-4*0.032 = about 1.41E-5 </span>
<span>H2CO3 ==> H^+ + HCO3^- </span>
<span>k1 = (H^+)(HCO3^-)/(H2CO3) </span>
<span>(H^+)= (HCO3^-) = x </span>
<span>(H2CO3) = 1.41E-5 </span>
<span>Solve for x = (H^+) and convert to pH. </span>
Answer:
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Explanation:
