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lianna [129]
3 years ago
13

Please help with this chemistry question, image attached.

Chemistry
1 answer:
koban [17]3 years ago
8 0

Answer:

The answer to your question is 0.67 moles of Glucose

Explanation:

Data

120 g of Glucose

convert to moles

Process

1.- Calculate the molar mass of Glucose

C₆H₁₂O₆ = (12 x 6) + (1 x 12) + (16 x 6)

              = 72 + 12 + 96

              = 180 g

2.- Remember that the molar mass of each molecule equals 1 mol. Use the rule of three to find the answer.

                        180 g ------------------- 1 mol

                         120 g ------------------ x                    

                         x = (120 x 1)/180

                         x = 120/180

                         x = 0.67 moles

3.- Conclusion

120 g of Glucose are equal to 0.67 moles.

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Answer:

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elements X is positively charged while Y will be negatively charged

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How can a short-term environmental change, such as a drought or a flood, affect organisms?
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Explanation:

hope this helps!

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The equilibrium concentrations of the reactants and products are [ HA ] = 0.260 M [HA]=0.260 M , [ H + ] = 2.00 × 10 − 4 M [H+]=
ValentinkaMS [17]

Answer:

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Explanation:

The dissolution reaction is:

HA ⇔ H⁺ + A⁻

So at equilibrium, Ka is calculated as below

Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260

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Hence, by definition,

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3 years ago
Methyl orange (HMO) is an acid-base indicator. Its two forms in solution are HMO (red) and MO- (yellow). When HMO is added to di
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Explanation:

Methyl orange is red in acid and yellow in base. When added to distilled water and the colour turns yellow, it means it is in its anion form. The equilibrium can be shifted towards the acid form (HMO) by adding acid. The acid will protonate the indicator shifting the position of equilibrium towards the acid side and the solution turns red.

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5. How much heat (in calories) is absorbed by a reaction when
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Answer:

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Explanation:

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We can calculate the heat released by the water (Q_w) when it cools using the following expression.

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According to the law of conservation of energy, the sum of the heat released by the water (Q_w) and the heat absorbed by the reaction (Q_r) is zero.

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