Answer: D
Find the answer in the explanation
Explanation:
Elastic solid will obey Hooke's law which state that the force applied is proportional to the extension provided the elastic limit is not exceeded.
Examples of Newtonian fluid are water, glycerol, honey and all organic solvents
When comparing solids to fluids, the below statement is true
We can therefore conclude that
For elastic solids, stress is linearly related to strain, and for Newtonian fluids, stress is linearly related to strain rate
Answer:
The drying time is calculated as shown
Explanation:
Data:
Let the moisture content be = 0.6
the free moisture content be = 0.08
total moisture of the clay = 0.64
total drying time for the period = 8 hrs
then if the final dry and wet masses are calculated, it follows that
t = (X0+ Xc)/Rc) + (Xc/Rc)* ln (Xc/X)
= 31.3 min.
Answer:
the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg
Explanation:
Given that:
Initial Temperature 
= 15°C
Initial Pressure 
= 5 atm
Final Pressure 
= 1 atm
Data obtain from steam tables of saturated water at 15°C are as follows:
Specific volume v = 1.001 cm³/gm
The change in temperature = 2°C
Specific heat of water = 4.19 J/gm.K
volume expansivity β = 1.5 × 10⁻⁴ K⁻¹
The expression to determine the change in temperature can be given as :
Δ T = 0.093 K
Now; we can calculate the lost work bt the formula:
where ;
is the temperature of the surrounding. = 20°C = (20+273.15)K = 293.15 K
From above the change in entropy is:
Thus, the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg
Answer:
-10.83m
Explanation:
Please see the attachment
This question is incomplete, the complete question is;
Find the magnitude of the steady-state response of the system whose system model is given by
dx(t)/dt + x(t) = f(t)
where f(t) = 2cos8t. Keep 3 significant figures
Answer: The steady state output x(t) = 0.2481 cos( 8t - 45° )
Explanation:
Given that;
dx(t)/dt + x(t) = f(t) where f(t) = 2cos8t
dx(t)/dt + x(t) = f(t)
we apply Laplace transformation on both sides
SX(s) + x(s) = f(s)
(S + 1)x(s) = f(s)
f(s) / x(s) = S + 1
x(s) / f(s) = 1 / (S + 1)
Therefore
transfer function = H(s) = x(s)/f(s) = 1/(S+1)
f(t) = 2cos8t → [ 1 / ( S + 1 ) ] → x(t) = Acos(8t - ∅ )
A = Magnitude of steady state output
S = jw
S = j8
so
A = 2 × 1 / √( 8² + 1 ) = 2 / √ (64 + 1 )
A = 2/√65 = 0.2481
∅ = tan⁻¹( 1/1) = 45°
therefore The steady state output x(t) = 0.2481 cos( 8t - 45° )
