Answer:

Explanation:
From the information given:
Life requirement = 40 kh = 40 
Speed (N) = 520 rev/min
Reliability goal
= 0.9
Radial load
= 2600 lbf
To find C10 value by using the formula:

where;


The Weibull parameters include:



∴
Using the above formula:


![C_{10} = 3640 \times \bigg[\dfrac{1248}{0.9933481582}\bigg]^{\dfrac{3}{10}}](https://tex.z-dn.net/?f=C_%7B10%7D%20%3D%203640%20%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1248%7D%7B0.9933481582%7D%5Cbigg%5D%5E%7B%5Cdfrac%7B3%7D%7B10%7D%7D)

Recall that:
1 kN = 225 lbf
∴


Answer:
The result might require 9 bits to store
Answer:
Java program explained below
Explanation:
FindSpecialNumber.java
import java.util.Scanner;
public class FindSpecialNumber {
public static void main(String[] args) {
//Declaring variable
int number;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
//getting the input entered by the user
System.out.print("Enter a number :");
number = sc.nextInt();
/* Based on user entered number
* check whether it is special number or not
*/
if (number == -99 || number == 0 || number == 44) {
System.out.println("Special Number");
} else {
System.out.println("Not Special Number");
}
}
}
_______________
Output#1:
Enter a number :-99
Special Number
Output#2:
Enter a number :49
Not Special Number