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Gelneren [198K]
3 years ago
9

Durante el segundo trimestre de 2001, Tiger Woods fue el golfista que más dinero ganó en el PGATour. Sus ganancias sumaron un to

tal de $5517777. De los 10 principales golfistas mejor remunerados, siete usaron pelotas de golf de la marca Titleist (sitio web de PGATour). Suponga que seleccionan al azar a dos de los 10 principales golfistas que ganan más dinero. Determine:
Engineering
1 answer:
ehidna [41]3 years ago
8 0

Answer: a. 0.4667

b. 0.4667 and C 0.0667

Explanation:

Given Data:

N = population size (10)

n = random selection (2)

r = number of observations = 7

Therefore

f(y) = ( r/y ) ( N - r / n - y ) / ( N /n )

When y = 1

f(1) = ( 7/1 ) ( 10 - 7 / 2 -1 ) / ( 10/2 )

= 7 / 15

= 0.4667

When y = 2

f(2) = ( 7/2 ) ( 10 - 7 / 2 -2 ) / ( 10/2 )

= 7 / 15

= 0.4667

When y = 0

f(0) = ( 7/0 ) ( 10 - 7 / 2 -0) / ( 10/2 )

= 1 / 15

= 0.0667

You might be interested in
1. A cylindrical casting is 0.3 m in diameter and 0.5 m in length. Another casting has the same metal is rectangular in cross-se
Lorico [155]

Based on the Chvorinov's rule, the diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the prism casting.

<h3>How to apply the Chvorinov's rule for casting processes</h3>

The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a <em>reference</em> time. This rule states that cooling time (<em>t</em>) is directly proportional to the square of the volume (<em>V</em>), in cubic meters, divided to the surface area (<em>A</em>), in square meters. Now we proceed to model each casting:

<h3>Cylindrical casting</h3>

t = C · [0.25π · D² · L/(0.5π · D² + π · D · L)]²

t = C · [0.25 · D · L/(0.5 · D + L)]²    (1)

<h3>Prism casting</h3>

t' = C · [3 · T² · L/(6 · T · L + 2 · T · L + 6 · T²)]²

t' = C · [3 · T · L/(8 · L + 6 · T)]²     (2)

<h3>Relationship between the cross sections of both castings</h3>

3 · T² = 0.25π · D²     (3)

Where:

  • <em>t</em> - Cooling time of the cylindrical casting, in time unit.
  • <em>t'</em> - Cooling time of the prism casting, in time unit.
  • <em>C</em> - Cooling factor, in time unit per square meter.
  • <em>D</em> - Diameter of the cylinder, in meters.
  • <em>L</em> - Length of the casting, in meters.
  • <em>T</em> - Width of the cross section of the prism casting, in meters.

If we know that <em>D =</em> <em>0.3 m</em>, then the thickness of the prism casting is:

T = \sqrt{\frac{\pi}{12} }\cdot D

<em>T ≈ 0.153 m</em>

<em />

And (1) and (2) simplified into these forms:

<h3>Cylindrical casting</h3>

t = C · {0.25π · (0.3 m) · (0.5 m)/[0.5 · (0.3 m) + 0.5 m]}²

t = 0.0329 · C     (1b)

<h3>Prism casting</h3>

t' = C · {3 · (0.153 m) · (0.5 m)/[8 · (0.5 m) + 6 · (0.153 m)]}²

t' = 0.00218 · C     (2b)

Lastly we find the <em>percentual</em> difference in the solidification times of the two castings by using the following expression:

<em>r = (</em>1 <em>- t'/t) ×</em> 100 %

<em>r = (</em>1 <em>-</em> 0.00218<em>/</em>0.0329<em>) ×</em> 100 %

<em>r =</em> 93.374 %

The <em>cooling</em> time of the <em>prism</em> casting is 6.626 % of the <em>solidification</em> time of the <em>cylindrical</em> casting. The diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the <em>prism</em> casting. \blacksquare

To learn more on solidification times, we kindly invite to check this verified question: brainly.com/question/13536247

3 0
3 years ago
Calculate the radius of gyration for a bar of rectangular cross section with thickness t and width w for bending in the directio
SVEN [57.7K]

Answer:

a)R= sqrt( wt³/12wt)

b)R=sqrt(tw³/12wt)

c)R= sqrt ( wt³/12xcos45xwt)

Explanation:

Thickness = t

Width = w

Length od diagonal =sqrt (t² +w²)

Area of raectangle = A= tW

Radius of gyration= r= sqrt( I/A)

a)

Moment of inertia in the direction of thickness I = w t³/12

R= sqrt( wt³/12wt)

b)

Moment of inertia in the direction of width I = t w³/12

R=sqrt(tw³/12wt)

c)

Moment of inertia in the direction of diagonal I= (w t³/12)cos 45=( wt³/12)x 1/sqrt (2)

R= sqrt ( wt³/12xcos45xwt)

4 0
4 years ago
4.A compression spring has a diameter of 0.67 in and a coil diameter of 0.067 in, with 30 total coils. The spring is to be made
Akimi4 [234]

Answer:

Fatigue factor of safety is 2.0267

Explanation:

Solution is attached below.

4 0
4 years ago
Before you calculate the moment capacity for a steel beam, you have to determine the classification of beam.
kirill [66]

Answer:

True

Explanation:

True - because different classification of steel beam have different yield strength.

The moment capacity for a steel beam is given by;

M = Mn / Ωₙ

where;

M - the maximum moment acting on the beam

Ωₙ - is the Safety Factor for Elements in Bending = 1.67

Mn - nominal moment of the steel, given as

M_n = Z_x *f_y

where;

Zₓ - the Plastic Section Modulus in the x or strong axis.

f_y - is the Yield Strength of the Steel (A36W, A46 W or A50W)

A36W = 36 ksi

A46 W = 46 ksi

A50W = 50 ksi

Thus, before you calculate the moment capacity for a steel beam, you have to determine the classification of beam, for the yield strength of the steel beam.

6 0
4 years ago
Propyl Benzhydryl Ether (continued on next page):
uranmaximum [27]

Answer:

See detailed explanation and image attached

Explanation:

1 mole of 1-pentanol reacts with 1 mole of benzhydrol

Number of moles in 1.5 g of benzhydrol = mass/molar mass = 1.5 g/184 g/mol = 0.008 moles of benzhydrol

x moles of 1-pentanol reacts with 0.008 moles of benzhydrol

x = 0.008 moles of 1-pentanol

If 1 mole occupies 22.4 L

0.008 moles occupies 22.4 * 0.008 moles = 0.179 L of 1-pentanol is required.

The mechanism of the formation of n-pentyl benzhydryl ether involves the protonation of the -OH group in benzhydrol. This is followed by loss of water molecule creating a carbocation which is attacked by the 1-pentanol.  Abstraction of a proton by a base completes the mechanism, regenerates the acid and yields the n-pentyl benzhydryl ether as shown in the image attached.

The synthesis of diethyl ether occurs by protonation of one ethanol molecule followed by SN2 attack by anothe ethanol molecule and a simultaneous loss of a water molecule. Deprotonation by a base yields the  diethyl ether

6 0
3 years ago
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