Answer:
Explanation:
From the given information:
Water freezing temp. 
Heat rejected temp 
Recall that:
The coefficient of performance is:

Again:
The efficiency given by COP can be represented by:

Finally; the power input in an hour can be determined by using the formula:

In hp; since 1 kW = 1.34102 hp
6.86kW will be = (6.86 × 1.34102) hp
= 9.199 hp
Answer: B
Explanation: unless newer models added wingding to code inside fused computer...wingdings on a window ...not a motor
Answer:
It would break I think need to try it out
Explanation:
Answer:
0.304 L of Freon is needed
Explanation:
Q = mCT
Q is quantity of energy that must be removed = 47 BTU = 47×1055.06 = 49587.82 J
C is specific heat of Freon = 74 J/mol.K = 74 J/mol.K × 1 mol/120 g = 0.617 J/g.K
T is temperature in the area of Mars = 189 K
m = Q/CT = 49587.82/(0.617×189) = 452.23 g = 452.24/1000 = 0.45223 kg
Density of Freon = specific gravity of Freon × density of water = 1.49 × 1000 kg/m^3 = 1490 kg/m^3
Volume of Freon = mass/density = 0.45223/1490 = 0.000304 m^3 = 0.000304×1000 = 0.304 L