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Aneli [31]
3 years ago
9

A network address of 172.16.0.0 /12 has been given. Which of the following accurately describes this network? (select one or mor

e)
(A) The ending address of this network is 172.255.255.255
(B) The ending address of this network is 172.31.255.255
(C) This is private class A network with 4 bits of sub-netting
(D) This is not a valid network address because the 255.240.0.0 mask is wrong
(E) This is private class B network using a default mask
Engineering
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

B and E is correct.

Explanation:

Given that network address

172.16.0.0/12

This is class B network type.

The ending of this network will be 172.31.255.255

In IP version 4 there are four following type of classes

1)Class A (0-127)

2)Class B (128-191)

3)Class C (191-223)

4)Class D(224-239)

5)Class E (240-255)

Generally class A,B,C and D are used.

So our options B and E is correct.

You might be interested in
If a bearing needs 4. 0 s to solidify enough for impact, how high must the tower be?.
maks197457 [2]
  1. The height of the tower is equal to 78.4 meters.
  2. The bearing's impact velocity is equal to 39.2 m/s.

<h3>How to determine the height of the tower?</h3>

In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

Where:

  • S represents the distance or height.
  • u represents the initial velocity.
  • a represents the acceleration.
  • t represents the time.

Substituting the given parameters into the formula, we have;

S = S₀ + ut - ½gt²

0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²

0 = S₀ - 4.9 × 16.0

Height, S₀ = 78.4 meters.

<h3>How to calculate the bearing's impact velocity?</h3>

In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

V = u - at

V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

Read more on velocity here: brainly.com/question/19365526

#SPJ1

Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

b. What is the bearing's impact velocity?

6 0
1 year ago
A 600-ha farmland receives annual rainfall of 2500 mm. There is a river flowing through the farmland with an inflow rate of 5 m3
shepuryov [24]

Answer:

E = 7333.33 mm

Explanation:

The annual evapotranspiration (E) amount can be calculated using the water budget equation:

P*A + Q_{in}*\Delta t = E*A + \Delta S + Q_{out}*\Delta t   (1)

<u>Where</u>:

<em>P: is the precipitation = 2500 mm, </em>

<em>Q(in): is the water flow into the river of the farmland = 5 m³/s, </em>

<em>ΔS: is the change in water storage = 2.5x10⁶ m³,  </em>

<em>Q(out): is the water flow out of the river of the farmland = 4 m³/s.</em>

<em>Δt: is the time interval = 1 year = 3.15x10⁷ s </em>

<em>A: is the surface area of the farmland = 6.0x10⁶ m² </em>  

Solving equation (1) for ET we have:

E = \frac{P*A + Q_{in}*\Delta t - \Delta S - Q_{out}*\Delta t}{A}

E = \frac{2.5 m \cdot 6.0 \cdot 10^{6} m^{2} + 5 m^{3}/s \cdot 3.15 \cdot 10^{7} s - 2.5 \cdot 10^{6} m^{3} - 4 m^{3}/s \cdot 3.15 \cdot 10^{7} s}{6.0\cdot 10^{6} m^{2}}                                  

E = 7333.33 mm

Therefore, the annual evapotranspiration amount is 7333.33 mm.

I hope it helps you!  

3 0
4 years ago
What is the angle of the input
olga55 [171]
Absolute positions — latitudes and longitudes
Relative positions — azimuths, bearings, and elevation angles
Spherical distances between point locations
3 0
3 years ago
What must engineers keep in mind so that their solutions will be appropriate?
vekshin1

Answer:

Context

Explanation:

It is of great value for an engineer to keep the context of his/her experiment in mind.

7 0
3 years ago
Sheet metal cutting operation along a straight line between two cutting edges is called Shearing Operation's. a)- True b)-False
AURORKA [14]

Answer: True

Explanation: The process in sheet metal which separates the metal sheet in straight line by cutting is known as shearing operation.The process of shearing is carried out by application of shearing forces on the metal sheet. this operation separates the metal sheet into two parts by the edges. They have the certain limited tolerance. Therefore the given statement in the question is true.

8 0
4 years ago
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