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Aneli [31]
3 years ago
9

A network address of 172.16.0.0 /12 has been given. Which of the following accurately describes this network? (select one or mor

e)
(A) The ending address of this network is 172.255.255.255
(B) The ending address of this network is 172.31.255.255
(C) This is private class A network with 4 bits of sub-netting
(D) This is not a valid network address because the 255.240.0.0 mask is wrong
(E) This is private class B network using a default mask
Engineering
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

B and E is correct.

Explanation:

Given that network address

172.16.0.0/12

This is class B network type.

The ending of this network will be 172.31.255.255

In IP version 4 there are four following type of classes

1)Class A (0-127)

2)Class B (128-191)

3)Class C (191-223)

4)Class D(224-239)

5)Class E (240-255)

Generally class A,B,C and D are used.

So our options B and E is correct.

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Air, at a free-stream temperature of 27.0°C and a pressure of 1.00 atm, flows over the top surface of a flat plate in parallel f
Morgarella [4.7K]

Answer:

Explanation:

Given that:

V = 12.5m/s

L= 2.70m

b= 0.65m

T_{ \infty} = 27^0C= 273+27 = 300K

T_s= 127^0C = (127+273)= 400K

P = 1atm

Film temperature

T_f = \frac{T_s + T_{\infty}}{2} \\\\=\frac{400+300}{2} \\\\=350K

dynamic viscosity =

\mu =20.9096\times 10^{-6} m^2/sec

density = 0.9946kg/m³

Pr = 0.708564

K= 229.7984 * 10⁻³w/mk

Reynolds number,

Re = \frac{SUD}{\mu} =\frac{\ SUl}{\mu}

=\frac{0.9946 \times 12.5\times 2.7}{20.9096\times 10^-^6} \\\\Re=1605375.043

we have,

Nu=\frac{hL}{k} =0.037Re^{4/5}Pr^{1/3}\\\\\frac{h\times2.7}{29.79\times 10^-63} =0.037(1605375.043)^{4/5}(0.7085)^{1/3}\\\\h=33.53w/m^2k

we have,

heat transfer rate from top plate

\theta _1 =hA(T_s-T_{\infty})\\\\A=Lb\\\\=2.7*0.655\\\\ \theta_1=33.53*2.7*0.65(127/27)\\\\ \theta_1=5884.51w

7 0
3 years ago
An engine operates on gasoline (LHV=44 MJ/kg) with a brake thermal efficiency of 37.9 % What is the brake specific fuel consumpt
scZoUnD [109]

Answer:

s =0.21\ kg/Kw.hr

Explanation:

Given that

Calorific value (CV) = 44 MJ/Kg

CV= 44,000 KJ/kg

Brake thermal efficiency(η) = 37.9 %

We know that

\eta =\dfrac{BP}{\dot{m_f}\times CV}

Where BP is the brake power

\eta =\dfrac{BP}{\dot{m_f}\times CV}

0.379 =\dfrac{BP}{\dot{m_f}\times 44000}

\dfrac{BP}{\dot{m_f}}=16676

Brake specific fuel consumption (s)

s =\dfrac{\dot{m_f}}{BP}

s =\dfrac{3600\times \dot{m_f}}{BP}

s =\dfrac{3600}{16,676}\ kg/Kw.hr

s =0.21\ kg/Kw.hr

7 0
3 years ago
The driving force for fluid flow is the pressure difference, and a pump operates by raising the pressure of a fluid (by converti
Lady_Fox [76]

Answer:

The maximum possible volume flow of gasoline is 0.543 m^3/s

Explanation:

Power = pressure differential × volume flow rate

Power = 3.8 kW

Pressure differential = 7 kPa

Volume flow rate = power ÷ pressure differential = 3.8 ÷ 7 = 0.543 m^3/s

3 0
4 years ago
I want a problems and there solutions of The inception of cavitation?​
Ugo [173]

Answer:

The overview of the given scenario is explained in explanation segment below.

Explanation:

  • The inception of cavitation, that further sets the restriction for high-pressure and high-free operation, has always been the matter of substantial experimental study over the last few generations.
  • Cavitation inception would be expected to vary on the segment where the local "PL" pressure mostly on segment keeps falling to that are below the "Pv" vapor pressure of the fluid and therefore could be anticipated from either the apportionment of the pressure.

    ⇒  A cavitation number is denoted by "σ" .

4 0
3 years ago
Foundation dampproofing is most commonly installed: Select one: a. on both the inside and outside of the basement wall b. Baseme
puteri [66]

Answer:A

Explanation:

Damp roof is generally applied at basement level which restrict the movement of moisture through walls and floors. Therefore it could be inside or the outside basement walls.

4 0
3 years ago
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