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valentina_108 [34]
1 year ago
10

(a) how many grams of water will be produced from the combustion of 3.36 g of ethane gas with 9.56 g of oxygen gas?

Chemistry
1 answer:
Sladkaya [172]1 year ago
5 0

4.609 grams of water will be produced from the combustion of 3.36 g of ethane gas with 9.56 g of oxygen gas. The chemical element with the atomic number 8 and symbol O is called oxygen.

Oxygen belongs to the periodic table's chalcogen group, is a very reactive nonmetal, and an oxidizing agent that easily produces oxides with most elements as well as other compounds.

The chemical formula for ethane, a paraffin series hydrocarbon with the properties of being colourless, odorless, and gaseous, is C2H6. The only hydrocarbon with a single carbon-carbon bond has the simplest structural makeup, and that is ethane. The primary use of ethylene, a feedstock for making plastics, is ethane.

A variety of intermediate products, the majority of which are transformed into plastics, are produced by the petrochemical industry using ethylene, which is primarily produced from ethane.

Learn more about ethane here:

brainly.com/question/19128101

#SPJ4

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You titrate 41.27 mL of 0.108 M Ca(OH)2 into 25.00 mL of citric acid (C6H307) (triprotic). What is the balanced equation and the
Triss [41]

Answer:

3Ca(OH)2 + 2C6H8O7 → 6H2O + Ca3(C6H5O7)2

And 0.119M is the concentration of the citric acid.

Explanation:

In an acid-base reaction, the proton H+ and the hydroxil ion OH- reacts producing water. The ions of the acid and base (C6H5O7³⁻ and Ca²⁺ ions produce the respective salt) as follows:

Ca(OH)2 + C6H8O7 → H2O + Ca3(C6H5O7)2

To balance the Calcium ions:

3Ca(OH)2 + C6H8O7 → H2O + Ca3(C6H5O7)2

To balance the C6H5O7³⁻ ions:

3Ca(OH)2 + 2C6H8O7 → H2O + Ca3(C6H5O7)2

And to balance the oxygens of water:

3Ca(OH)2 + 2C6H8O7 → 6H2O + Ca3(C6H5O7)2

And this is the balanced reaction.

The moles of Ca(OH)2 that reacts are:

41.27mL = 0.04127L * (0.108mol/L) = 0.004457 moles Ca(OH)2

<em>Moles of citric acid:</em>

0.004457 moles Ca(OH)2 * (2mol C6H8O7 / 3mol Ca(OH)2) = 0.002971 moles C6H8O7

In 25.00mL = 0.02500L:

0.002971 moles C6H8O7 / 0.0250L =

<h3>0.119M</h3>

6 0
3 years ago
What is the total pressure in atmospheres in a 10.0L vessel containing 2.50 x 10-3 mol H2, 1.00 x 10-3
grigory [225]

Answer:

Total pressure = 16.42× 10⁻⁹atm

Explanation:

Given data:

Moles of H₂ = 2.50 × 10⁻³ mol

Moles of He = 1.00 × 10⁻³ mol

Mass of Ne = 3 × 10⁻⁴ mol

Volume = 10 L

Temperature = 35°C

Total pressure = ?

Solution:

Pressure of hydrogen:

P = nRT / V

P = 2.50 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 63.22× 10⁻³  atm. L /10 L

P = 6.3 × 10⁻³atm

Pressure of helium:

P = nRT / V

P = 1.00 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 25.29 × 10⁻³ atm. L /10 L

P = 2.53× 10⁻³ atm

Pressure of neon:

P = nRT / V

P = 3 × 10⁻⁴ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 75.86× 10⁻³ atm. L /10 L

P = 7.59× 10⁻³ atm

Total pressure of mixture:

P(mixture)  = pressure of hydrogen + pressure of helium+ pressure of neon

P(mixture)  = 6.3 × 10⁻³atm + 2.53× 10⁻³ atm + 7.59× 10⁻³ atm

P(mixture) = 16.42× 10⁻⁹atm

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