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Reil [10]
3 years ago
10

A compound is found to be 38.76% calcium, 19.97% phosphorous and 41.28% oxygen. What is the empirical formula for this compound?

Chemistry
1 answer:
motikmotik3 years ago
3 0

The empirical formula is Ca₃P₂O₈.

<em>Assume</em> that you have 100 g of the compound.

Then you have 38.76 g Ca, 19.97 g P, and 41.28 g O.

Now, we must convert these <em>masses to moles</em> and <em>find their ratio</em>s.

If the number in the ratio are not close to integers, you <em>multiply them by a numbe</em>r that makes them close to integers.

From here on, I like to summarize the calculations in a table.

<u>Element</u>  <u>Mass/g</u>     <u> Moles  </u>      <u> </u><u>Ratio </u>    <u>   ×2    </u>   <u>Integers</u>  

     Ca       38.76      0.967 07     1.4998   2.9995         3

     P         19.97       0.644 82     1             2                   2

     O        41.28       2.580 0       4.0011   8.0023          8

The empirical formula is Ca₃P₂O₈.


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Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for  B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = Ae^{\frac{-E_{a} }{RT} }

Where

k = rate constant

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T = temperature  (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = Ae^{\frac{-95000}{(8.314)(298)} }

And for B the rate constant k₂ is given by k₂ = Ae^{\frac{-74200 }{(8.314)(298)} }

k₁ = A×2.225×10⁻¹⁷

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As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

3 0
3 years ago
Give the volume indicated. Be sure to include all significant figures.
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Answer: -

71

Explanation: -

From the diagram, we see that volume goes from 70 to 75 in 5 markings.

Each marking is for 1.

It is the most accuracy possible as there is no smaller marking.

Significant figures expresses the required amount of accuracy.

Thus the volume indicated from the diagram is 71 .

8 0
3 years ago
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Calculate the frequency and wavelength for a photon of light with an energy of 3.2x10-19 J.
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Answer:

wavelength = 6×10⁻⁷m

f = 0.5 ×10¹⁵ Hz

Explanation:

Given data:

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Wavelength of photon = ?

Frequency of photon = ?

Solution:

E = h.f

f = frequency

h = planck's constant

E = energy

f = E/h

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s⁻¹ = Hz

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speed of light = wavelength × frequency

wavelength = speed of light / frequency

wavelength =  3×10⁸ m.s⁻¹ /0.5 ×10¹⁵s⁻¹  

wavelength = 6×10⁻⁷m

6 0
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The greenhouse effect can be compared to...
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