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Reil [10]
3 years ago
10

A compound is found to be 38.76% calcium, 19.97% phosphorous and 41.28% oxygen. What is the empirical formula for this compound?

Chemistry
1 answer:
motikmotik3 years ago
3 0

The empirical formula is Ca₃P₂O₈.

<em>Assume</em> that you have 100 g of the compound.

Then you have 38.76 g Ca, 19.97 g P, and 41.28 g O.

Now, we must convert these <em>masses to moles</em> and <em>find their ratio</em>s.

If the number in the ratio are not close to integers, you <em>multiply them by a numbe</em>r that makes them close to integers.

From here on, I like to summarize the calculations in a table.

<u>Element</u>  <u>Mass/g</u>     <u> Moles  </u>      <u> </u><u>Ratio </u>    <u>   ×2    </u>   <u>Integers</u>  

     Ca       38.76      0.967 07     1.4998   2.9995         3

     P         19.97       0.644 82     1             2                   2

     O        41.28       2.580 0       4.0011   8.0023          8

The empirical formula is Ca₃P₂O₈.


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7 0
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sergejj [24]

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7 0
3 years ago
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Hey there,


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Hope this helps.
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