Answer:
CaO
Explanation:
Firstly, let’s get the percentage compositions.
The total mass is now = 4.008 + 1.600 = 5.608g
The percentage composition of carbon is thus 4.008/5.608 * 100 = 71.47%
The percentage composition of oxygen is 100 - 71.4 = 28.53%
Now, we divide each percentage by the atomic masses. The atomic mass of calcium is 40 while that of oxygen is 16
Ca = 71.47/40 = 1.78675
O = 28.53/16 = 1.783125
Both values are quite similar and dividing by the smallest will yield same values of 1.
Hence , the empirical formula is caO
How can H2 form if only one side has Hydrogen in it ?
apparently it’s saline water.
Answer: -
15.55 M
35.325 molal
Explanation: -
Let the volume of the solution be 1000 mL.
Density of nitric acid = 1.42 g/ mL
Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid
= 1000 mL x 1.42 g/ mL
= 1420 g.
Percentage of HNO₃ = 69%
Amount of HNO₃ =
= 979.8 g
Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol
Number of moles of HNO₃ =
= 15.55 mol
Molarity is defined as number of moles per 1000 mL
We had taken 1000 mL as volume and found it to contain 15.55 moles.
Molarity of HNO₃ = 15.55 M
Mass of water = Total mass of nitric acid solution - mass of nitric acid
= 1420 - 979.8
= 440.2 g
So we see that 440.2 g of water contains 15.55 moles of HNO₃
Molality is defined as number of moles of HNO₃ present per 1000 g of water.
Molality of HNO₃ =
= 35.325 molal
1.AIH3O3
2.Na2O4S
3.BrLi
4.KF
5.MgN2O6
6.Sr3N2
7.CaCO3
All numbers should be subscripts