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DIA [1.3K]
4 years ago
8

Which statement describes a problem with the peer review process in scientific research?

Chemistry
1 answer:
Snezhnost [94]4 years ago
6 0
Its A.It can sometimes reject important new ideas or novel techniques.<span>
</span>
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What is the answer <br> A. North <br> b. South <br> C.east <br> D west
ANTONII [103]
I think it’s C because he would push off of the sled
5 0
3 years ago
What do we call the rows on the periodic table?<br>A. period<br>B. family<br>C. group<br>D. metals
TEA [102]

I am pretty sure the answer is periods. Hope it helps. If not what are the answer choices?

3 0
3 years ago
Read 2 more answers
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Dafna11 [192]

This hypothetical process would produce actinium-230.

<h3>Explanation</h3>

An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.

There are two types of beta decay: beta minus β⁻ and beta plus β⁺.

The mass number of a nucleus <em>stays the same</em> in either process. In β⁻ decay, the atomic number <em>increases </em>by one. An electron e⁻ is produced. In β⁺ decay, the atomic number <em>decreases </em>by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.

β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.

Gamma decays do not influence the atomic or mass number of a nucleus.

Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.

The overall nuclear reaction would involve five different particles. On the reactant side, there is

  • one uranium-238 atom.

On the product side, there are

  • one actinium-230 atom,
  • two alpha particles (a.k.a. helium-4 nuclei),
  • one electron, and
  • one gamma particle (a.k.a. photon).

\;_{\phantom{2}92}^{238} \text{U} \to \;_{\phantom{2}89}^{230} \text{Ac} + \;_{2}^{4} \text{He} + \;_{2}^{4} \text{He} + \text{e}^{-} + \gamma

Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?

8 0
3 years ago
In the following chemical equation, which are the reactants?
Airida [17]
In the following chemical equation, which are the reactants?
2HF + Mgo MgF2 + 2H20
>
A. 2HF + MgF2
B. 2H+ + Mgo
C. MgF2 + H20
D. MgO + H20
A
B
D
In the following chemical equation, which are the reactants?
2HF + Mgo MgF2 + 2H20
>
A. 2HF + MgF2
B. 2H+ + Mgo
C. MgF2 + H20
D. MgO + H20
A
B
D
3 0
3 years ago
2. You have a rock with a<br> volume of 15cm3 and a<br> mass of 45 g. What is its<br> density?
babymother [125]

Answer:

3 g/cm³

Explanation:

Density= Mass divided by Volume

45÷15= 3

3 0
3 years ago
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