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Tema [17]
2 years ago
14

Why are measurements important for science? Give two reasons. Please help meeee :(

Chemistry
1 answer:
stepladder [879]2 years ago
4 0

Answer:

-Being in the service of quality, safety, designing and problem solving.

-It plays an importnat part in our lives too, to measure any surface, object, etc.

Explanation:

Measurement is perhaps one of the most fundamental concepts in science. Without the ability to measure, it would be difficult for scientists to conduct experiments or form theories.

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Which compound has the highest percent composition by mass of strontium
8090 [49]
So if the compound has the smallest gram formula mass it has the highest percentage composition by mass of strontium
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3 years ago
Could someone help me with this? No links, will give brainliest.
Ganezh [65]

Answer: I think it represents the SiO

Explanation:

6 0
3 years ago
What mass of sodium chloride contains 4.59 x 10 24 formula units?
shtirl [24]
The term formula units means molecules.

Then, what you are looking for is the mass in 4.59*10^24  molecules.

The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.

1) Number of moles = 4.59 * 10^24 molecules / (6.02 * 10^23 molecules/mol) = 7.62 mol

2) Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

3) mass of NaCl = molar mass *  number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl

Answer: 445.31 g of NaCl.

 
7 0
3 years ago
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5 0
2 years ago
Consider the following reaction: C6H6 + O2 \longrightarrow ⟶ CO2 + H2O 39.7 grams of C6H6 are allowed to react with 105.7 g of O
Ivenika [448]

Answer:

116.3 grCO2

Explanation:

1st - we balance the equation so that it finds the same amount of elements of the product side and of the reagent side

C6H6 +15/2 O2⟶ 6CO2 +3 H2O

2nd - we calculate the limiting reagent

39.2gr C6H6*(240grO2/78grC6H6)=120 grO2

we don't have that amount of oxygen so this is the excess reagent and oxygen the limiting reagent

3rd - we use the limiting reagent to calculate the amount of CO2 in grams

105.7grO2*(264grCO2/240grO2)=116.3 grCO2

7 0
2 years ago
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