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1 year ago

URGENT!! ILL GIVE

Physics

1 answer:

MAXImum [283]1 year ago

6 0

Answer:

Explanation:

because both energy and temperature ️ increase both are related.

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A 50 Q resistor in a circuit has a current flowing through it of 2.0 A. What is

Alex17521 [72]

Hello!

We can use the following equation for calculating power dissipated by a resistor:
$P = i^2R$

P = Power (? W)
i = Current through resistor (2.0 A)
R = Resistance of resistor (50Ω)

Plug in the known values and solve.

$P = (2.0^2)(50) = \boxed{\text{ B. }200 W}$

7 0

1 year ago

When the velocity of an object Changes it is acted upon by a

anygoal [31]

When the velocity of an object changes, it is acted upon by a force

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3 years ago

A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800

Arada [10]

Explanation:

The given data is as follows.

m = 5000 kg, h = 800 km = $0.8 \times 10^{6} m$

$R_{e} = 6.37 \times 10^{6} m$ , r = R + h = $7.17 \times 10^{6} m$

$M_{e} = 5.98 \times 10^{24}$ kg, G = $6.67 \times 10^{-11} Nm^{2}/kg^{2}$

As we know that,

$\frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}$

v = $\sqrt{\frac{GM_{e}}{r^{2}}}$

And, it is known that formula to calculate angular velocity is as follows.

$\omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}$

v = $\sqrt{\frac{GM_{e}}{r^{3}}}$

= $\sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}$

= $1.0402 \times 10^{-3} rad/s$

Thus, we can conclude that speed of the satellite is $1.0402 \times 10^{-3} rad/s$ .

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2 years ago

A(n) signal carries information by copying an original sound.

viva [34]

An analog signal carries information by copying an original sound
When we speak through the microphone, it turns our sound into some sort of electronic wave.
This electronic wave is caught by a recording device and later could be replicated into Mp3 file that we usually listen to

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2 years ago

Read 2 more answers

a object with a mass of 70 kilograms is supported at a height 8 meters above the ground.what's the potential energy of the objec

Agata [3.3K]

Potential Energy = mgh,

where m = mass in kg, g ≈ 10 m/s², h = height above ground = 8 m

PE = mgh

= 70*10*8 = 5600 J

7 0

3 years ago