Answer:
the horizontal distance covered by the cannonball before it hits the ground is 327.5 m
Explanation:
Given;
height of the cliff, h = 210 m
initial horizontal velocity of the cannonball, Ux = 50 m/s
initial vertical velocity of the cannonball, Uy = 0
The time for the cannonball to reach the ground is calculated as;
The horizontal distance covered by the cannonball before it hits the ground is calculated as;
Therefore, the horizontal distance covered by the cannonball before it hits the ground is 327.5 m
Answer:
The value is 
Explanation:
From the question we are told that
The speed is 
The radius of the earth is 
Generally the circumfernce of the earth is mathematically evaluated as
=> 
=> 
Generally the time taken is mathematically represented as
Converting to days
=>
Answer:
70.6 mph
Explanation:
Car A mass= 1515 lb
Car B mass=1125 lb
Speed of car B is 46 miles/h
Distance before locking, d=19.5 ft
Coefficient of kinetic friction is 0.75
Initial momentum of car B=mv where m is mass and v is velocity in ft/s
46 mph*1.46667=67.4666668 ft/s
Initial momentum of car A is given by
where 
is velocity of A
Taking East as positive and west as negative then the sum of initial momentum is
The common velocity is represented as 
hence after collision, the final momentum is
From the law of conservation of linear momentum, sum of initial and final momentum equals each other hence
The acceleration of two cars 
From kinematic equation
hence
Substituting the value of in equation
Answer:
0.625m
Explanation:
Now Velocity of a wave ,V = frequency × wavelength
Wavelength =velocity /frequency
=500/800 =0.625m
I believe the correct answer is C
