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slavikrds [6]
3 years ago
8

A man inside the water seea a fish in water. will the fish appear to man in it's actual position? will the man appear to fish in

his actual position?​
Physics
2 answers:
weqwewe [10]3 years ago
4 0

Answer:

no

Explanation:

due to the refraction of light,meaning bending of light when it passes from diffrent mediums with diffrent densities

(probably mot the complete ans but smtg like this)

fiasKO [112]3 years ago
3 0
No man will not even go near and fish will but not same position
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Name one reason why you should pour milk in before cereal.
krok68 [10]

Answer:

splashing

Explanation:

if you put in the cereal after the milk it will splash everywhere, causing a waste of milk, and a loss of time.

5 0
3 years ago
Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he
likoan [24]

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

8 0
3 years ago
The velocity v(t) in the table below is increasing for 0_t_12.
katen-ka-za [31]
<span>When n=4 subdivisions distance traveled = 40 X 12 = 480

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List 5 signs of a chemical change?
iris [78.8K]

Answer:

Color, formation, gas, odor,

Explanation:

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4 0
3 years ago
A 5.00 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en
Brut [27]

Answer:

75 N

Explanation:

In this problem, the position of the crate at time t is given by

y(t)=2.80t+0.61t^3

The velocity of the crate vs time is given by the derivative of the position, so it is:

v(t)=y'(t)=\frac{d}{dt}(2.80t+0.61t^3)=2.80+1.83t^2

Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:

a(t)=v'(t)=\frac{d}{dt}(2.80+1.83t^2)=3.66t [m/s^2]

According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:

F(t)=ma(t)

where

m = 5.00 kg is the mass of the crate

At t = 4.10 s, the acceleration of the crate is

a(4.10)=3.66\cdot 4.10 =15.0 m/s^2

And therefore, the force on the crate is:

F=ma=(5.00)(15.0)=75 N

7 0
3 years ago
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