When we hit the puck from tap the puck will move forward.
This is due to the impulse provided by us at the time of hit. Due to this impulse the puck will move forward and start moving in some direction.
As soon as puck move forward the force on it is zero as the weight of the puck is counterbalanced by the air stream force and there is no other force on it so puck will continue its motion till it will hit at some other point.
So here the motion of the puck will be uniform motion till it will collide with some other points.
So here the correct option will be given as
<em>moves with a constant speed until hitting the other end.</em>
Emit greenhouse gases
Explanation:
Nuclear power is regarded as a clean energy source because it doesn't produce or emit greenhouse gases.
Greenhouse gases are mostly generated by the use of fossil fuels that pollutes the environment causing surging global temperature.
Nuclear power is produced by the splitting of radioactive minerals in rods. The process releases a large amount of energy. When the fuel elapses, only radioactive wastes remains.
There is no production of any greenhouse gas in the process of harnessing nuclear energy.
This is why it is considered a clean energy source.
learn more:
Non-renewable resources brainly.com/question/2948717
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Answer:
Required diameter of hose pipe = 0.2864 mm
Solution:
From the continuity eqn, the fluid flow rate is given by:
Av = 
where
A = cross-sectional area = 
r = hose pipe radius
v = velocity of gas
Also, 
Using:
1 gallon = 3.854 l
1 mile = 1609.34 m

Therefore,






The diameter of the hose pipe = 2r = 
The diameter of the hose pipe = 
If gravity had no effect on a ball after you threw it ... and there also
were no air to slow it down ... then the ball would continue traveling
in a straight line, in whatever direction you threw it.
That's the heart and soul of Newton's laws of motion ... any object
keeps moving at the same speed, and in a straight line in the same
direction, until a force acts on it to change its speed or direction.\
If you threw the ball horizontally, then it would keep moving in the
same direction you threw it. But don't forget: The Earth is not flat.
The Earth is a sphere. So, as the ball kept going farther and farther
in the same straight line, the Earth would curve away from it, and it
would look like the ball is getting farther and farther from the ground.
Answer:
Therefore,
The speed of the wave on the longer wire is 95 m/s.
Explanation:
Given:
For Short wire, speed is

Let length of Short and Longer wire be
such that

To Find:
Speed on the longer wire
Solution:
The speed of a pulse or wave on a string under tension can be found with the equation,

Where,
= Tension on the wire
L = Length of Sting
m = mass of String
So here we have,
= same

Therefore,
......equation ( 1 )
And
.......equation ( 2 )
Dividing equation 1 by equation 2 and on Solving we get

Therefore,

Therefore,
The speed of the wave on the longer wire is 95 m/s.