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Vlad1618 [11]
4 years ago
15

00.25 divided by 0.07

Mathematics
2 answers:
Airida [17]4 years ago
6 0
I would say it’s 27/7
kipiarov [429]4 years ago
4 0
Here is ur answer
0.357142857142857
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The school counselor needs to meet with students who have more than three absences. Here is some of the data about the students.
frosja888 [35]

Answer:

The individuals in this data set are students. This data set contains 2 variables, 1 of which is quantitative.

Step-by-step explanation:

Individuals are the people or things described by a data set.

Variables are characteristics of the individuals that we measure or observe.

Categorical variables take on values that are labels or categories, and quantitative variables take on numerical variables.

The individuals described by this data set are students.

The characteristics listed--homeroom teacher and absences--describe each of the students, not teachers or counselors.

One of the variables--absences--is quantitative.

7 0
3 years ago
Monica plans to buy markers and colored pencils at an office supply store A box of markers cost $3.85 and a a box of colored pen
serg [7]

Answer:

Step-by-step explanation:

m=7

c=5

balance=26.802

8 0
3 years ago
If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)( ) = . The check of the polynomial division problem shows that the product of
azamat

Answer:

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

Step-by-step explanation:

Given

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

(x + 7) * (\ ) = [\ ]

Required

Complete the blanks

We have:

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

Rewrite as:

\frac{(3x^2 + 22x + 7) }{ (x + 7)} = 3x + 1

Cross multiply

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

8 0
3 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that n = 292, \pi = \frac{52}{292} = 0.178

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

3 0
3 years ago
Solve for x: |x − 2| + 10 = 12 (1 point)
True [87]

Answer:

I think that would be 1

Step-by-step explanation:

Do everything in the lines before anything else. -2 becomes a 2 and then you add that with the 12 and divide 12 on both sides to get one.

6 0
2 years ago
Read 2 more answers
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