Question

How much of the initial mass remains after 80 years? (Round your answer to three decimal places.)

Answer 1

Given

$y=11(\frac{1}{2})^{\frac{t}{30}}$

When t = 80

We substitute for t

$y=11(\frac{1}{2})\frac{}{}^{\frac{80}{30}}$

Simplify

$y=11(\frac{1}{2})^{\frac{8}{3}}$

Simplify further

$y=1.732g$

The final answer