Order the following numbers from least to greatest. 64 cubicle root 18 cubicle root 4.2

Mathematics

1 answer:

Mrrafil [7]3 years ago

3 0

It would be 4.2, 19 cubic root, and 64 cubic root (least to greatest)

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What is the following product? ^3 square root 24 times ^3 square root 45

torisob [31]

Answer:

$6 \sqrt[3]{5}$

Step-by-step explanation:

For the problem, $\sqrt[3]{24} *\sqrt[3]{45}$ , use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.

$\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}$

You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.

$\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}$