The graph of a quadratic function y = ax² is a VERTICAL parabola open upward or downward depending whether a (the coefficient of x) is positive or negative
The graph y² = ax or y = √ax is a HORIZONTAL parabola open to the right or to the left depending whether a (the coefficient of x) is positive or negative
Answer:
It would be undefined if the line is vertical.
Step-by-step explanation:
Answer:
2 sqrt(5) OR 4.5
Step-by-step explanation:
You have to know Pythagorean theorem to solve this question.
a^2 + b^2 = c^2
To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:
b^2 + 8^2 = 10^2
But it would've come out the same. The unlabeled side is 6.
We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.
4^2 + x^2 = 6^2
16 + x^2 = 36 subtract 16 from both sides.
x^2 = 20
Take the square root of both sides.
sqrt (x^2) = sqrt 20
x = 2 sqrt(5) which is approximately 4.472.
2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.
I'm guessing this is a question about interest rates? If you have $20 that increases by 4% in one year, you need to multiply 20 by 1.04. This gets you $20.8.
If you are talking about compound interest, we will take this number and multiply it again by 1.04 for the second year. 20.8 x 1.04 = $21.632.
If it is instead simple interest, we will simply add another .8 dollars for each year, instead of getting 4% interest compounded every year onto the new value. This gets you $21.6.
Answer:
Option 3 is the correct answer.
Step-by-step explanation:
In this graph the red area is above the line y = -1 which represents y ≥ (-1)
Another graph is of a line y = mx + c which passes through (2, -1) and (0, 0)
where m = (y-y')/(x-x') = (1+0)/(0-2) = -1/2
and y intercept c = 0
Therefore line is y = -1/2x
and the blue area will be y ≤ -1/2x below the line.
Hence Option 3 is the answer.
