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BaLLatris [955]
3 years ago
7

A master student is planning to take a qualifying exam in the coming summer. She has three chances. The first one is in June. If

she fails the 1st one, then she can have a 2nd try in July, and if she also fails that one, she will take the 3rd one in August. If she fails all three exams, then she is not qualified. The chance of passing the 1st one is 0.5, the chance of passing the 2nd one is 0.7, and the chance of passing the 3rd one is 0.8. And these chances are independent. a) What is the probability that she passes the qualification? b) Given that she passes the qualification, what is the conditional probability that she passes on the second try?
Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:

Step-by-step explanation:

Given

P_1=Probability of clearing exam in 1 st attempt=0.5

P_2=Probability of clearing exam in 2 nd attempt=0.7

P_3=Probability of clearing exam in 3 rd attempt=0.8

Probability that she passes the exam=P(1 st\ attempt)+P(1\ fail)\cdot P(2\ pass)+P(1\ fail)\cdot P(2\ fail)\cdot P(3 rd pass)

P=0.5+0.5\times 0.7+0.5\times 0.3\times 0.8=0.97

(b)P(Pass qualification on 2nd try|passes qualification)

P(Pass qualification on 2nd try|passes qualification)=\frac{P(fail\ on\ 1 )\cdot P(pass\ in\ 2nd)}{P(passes)}

P(Pass qualification on 2nd try|passes qualification)=\frac{0.5\times 0.7}{0.97}=0.3608

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4.77

Step-by-step explanation:

because Circumference can be found with this equation

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we need to plug in 15 for Circumference and solve for its radius or R.

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but we need diameter which is 2R so we just need to multiply the answer by 2.

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Ivanshal [37]

Answer:the weight after 225 days is

22885 kilograms

Step-by-step explanation:

The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.

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