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allochka39001 [22]
4 years ago
7

If cos⁡ x=7/25, and 0

Mathematics
1 answer:
tatiyna4 years ago
7 0

Answer:

Need the rest of the equation

Step-by-step explanation:

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I need help with this please. :)
jek_recluse [69]

9514 1404 393

Answer:

  1. 2x
  2. 2
  3. 128x +640

Step-by-step explanation:

1.

  \displaystyle\frac{8x^2-4x}{4x-2}=\frac{4x(2x-1)}{2(2x-1)}=\boxed{2x}

__

2.

  \displaystyle\frac{8x-4}{x+3}-\frac{12x-20}{2x+6}=\frac{8x-4}{x+3}-\frac{4(3x-5)}{2(x+3)}=\frac{8x-4-2(3x-5)}{x+3}\\\\=\frac{8x-4-6x+10}{x+3}=\frac{2x+6}{x+3}=\frac{2(x+3)}{x+3}=\boxed{2}

__

3.

  \displaystyle\frac{(2x+10)^7}{(x+5)^6}=\frac{(2(x+5))^7}{(x+5)^6}=2^7(x+5)^{7-6}=128(x+5)\\\\=\boxed{128x+640}

5 0
3 years ago
State the domain and range of the relation. Determine whether the relation represents a function.
dangina [55]

Answer:

Domain {-2,0,2}

Range {-2,0,2}

Relation is a Function

Step-by-step explanation:

We are given a relation:

{ (-2,-2) , (0,0) , (2,2) }

Domain can be defined as the all possible values of x for a relation. It is considered as a set of all first values of the ordered pairs of a given relation.

Domain of the given relation is {-2,0,2}

Range can be defined as all possible value of y which corresponds to the values of x in the domain. It is considered as a set of all second values of the ordered pairs of a given relation.

Range of the given relation is {-2,0,2}

A relation is a function if only there is one value of y for each value of x. If in the set of ordered pair of the relation, the value of x gets repeated, then the relation is not a function.

As no values of x are getting repeated, the relation is a function.

4 0
3 years ago
How do i answer these?
Harrizon [31]
The Aon Center is taller. You just need to look at the place values, like 5 and 10. Which is bigger? the ten of course. 
5 0
4 years ago
Geometry help plz will mark brainliest.
Alex17521 [72]
I think it's 12x.
I'm not a 100% sure though, but I hope this helps. =^D
5 0
3 years ago
Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean
Maksim231197 [3]

The correct option is:   a female who weighs 1500 g

<em><u>Explanation</u></em>

<u>Formula for finding the z-score</u> is:  z= \frac{X-\mu}{\sigma}

Newborn males have weights with a mean(\mu) of 3272.8 g and a standard deviation(\sigma) of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69

According to the normal distribution table,  P(z=-2.69)=0.0036 = 0.36\%

Now, newborn females have weights with a mean(\mu) of 3037.1 g and a standard deviation(\sigma) of 706.3 g.


So, the z-score for the newborn female who weighs 1500 g will be.......

z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18

According to the normal distribution table,  P(z=-2.18)=0.0146 = 1.46\%

As we can see that the <u>probability that a newborn female has weight of 1500 g is greater than newborn male</u>,  so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0
3 years ago
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