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Vilka [71]
1 year ago
12

k h S Which of the following is a true proportion of the figure based on the triangle proportionality theorem?​

Mathematics
1 answer:
erastova [34]1 year ago
5 0

The true proportion of the figure based on the triangle proportionality theorem is Option (A).

What is the basic proportionality theorem?

According to the Basic Proportionality Theorem (BPT), if a line is parallel to a triangle's side that divides the other sides into two separate points, the line will divide those sides proportionately.

Given that TU is parallel to QR, by the proportionality theorem, we get

\frac{ST}{TQ} = \frac{SU}{UR}

or, \frac{k}{j} = \frac{h}{i}

or, \frac{i}{j} = \frac{h}{k}

Ans:  \frac{i}{j} = \frac{h}{k}

Hence, a true proportion of the figure based on the triangle proportionality theorem is (A)  \frac{i}{j} = \frac{h}{k}

To learn more about the proportionality theorem

brainly.com/question/8160153

#SPJ1

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Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

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2.

q^0=1

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2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

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5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

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\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

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