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solmaris [256]
2 years ago
6

Sarah uses three and one-half pounds of clay to make 14 small vases. Use a proportion to find how many pounds of clay she will u

se to make 31 small vases.
A 12 and one half pounds
B 8 and three-fourths pounds
C 7 and three-fourths pounds
D 6 and one-half pounds
Mathematics
1 answer:
Snezhnost [94]2 years ago
5 0

Answer:

C

Step-by-step explanation:

(3.5 to 14)×10=

(35 to 140)÷7=

(5 to 20) which equals 1/4

so every pound of clay, 4 vases can be made

31÷4=7.75

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If f(x) = 2x2 +5/(x-2), complete the following statement:
faust18 [17]

For this case we have the following function:

f (x) = 2x ^ 2 + \frac {5} {x-2}

By definition, we have that the domain of a function is given by all the values for which the function is defined. The given function is not defined when the denominator is zero.

So:

x-2 = 0\\x = 2

Thus, the function is not defined at x = 2.

The domain is given by all real numbers except 2.

Answer:

The domain is given by all real numbers except 2.

3 0
3 years ago
Please help! I need help with this question.
musickatia [10]

Answer:

B

Step-by-step explanation:

the supplement is the angle that will add to the other angle to get 180 degrees. 180-129=51 which is B.

8 0
3 years ago
Which statement correctly describes the graph of y = x + 9.5?
Vikki [24]

Answer:

A is the answer

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Identify all solutions for a triangle with A = 38 degrees b = 10, and a= 8. Round to the nearest tenth.
rjkz [21]

Answer:

A = 38°

B = 50.32°

C = 91.68°

a = 8

b = 10

c = 12.77

Step-by-step explanation:

The first thing is to find the angle B, like this:

sin B = b * sin A / a = 10 * sin (38 °) / 8

sin B = 0.77

B = arc sin (0.77)

B = 50.32 °

For angle C, it would be:

C = 180 - 38 - 50.32

C = 91.68 °

Side c, we calculate it like this:

c = a * sin C / sin A = 8 * sin (91.68 °) / sin (38 °)

c = 12.77

5 0
4 years ago
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0
3 years ago
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