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nexus9112 [7]
1 year ago
12

A thermogram taken outside a house shows high amounts of thermal energy around the windows but not around the roof. which conclu

sion supports the thermogram?
Computers and Technology
1 answer:
mestny [16]1 year ago
4 0

The conclusion sustains the thermogram will be that the windows are not energy efficient, but the roof stands energy efficient.

<h3>What is Thermography?</h3>

Thermography exists a noninvasive method that employs an infrared camera to develop pictures that depict patterns of heat and blood flow on or around the body's surface. A thermogram taken outside a house shows high quantities of thermal energy around the windows but not around the roof. The conclusion that supports the thermogram will be that the windows are not energy efficient, but the roof exists energy efficient.

Thermal energy (also named heat energy) is produced when a rise in temperature pushes atoms and molecules to move faster and collide with each other. The energy that reaches the temperature of the heated substance is named thermal energy. The term "thermal energy" exists utilized loosely in various contexts in physics and engineering. It can guide several different well-defined physical concepts.

To learn more about Thermography refer to:

brainly.com/question/1500896

#SPJ4

The complete question is,

A thermogram taken outside a house shows high amounts of thermal energy around the windows but not around the roof.

Which conclusion supports the thermogram?

The windows and the roof are energy efficient.

The windows and the roof are not energy efficient.

The windows are not energy efficient, but the roof is energy efficient.

The windows are energy efficient, but the roof is not energy efficient.

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Answer:It rearranges the files on a hard drive to get quicker access to them.

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2 years ago
Write a program to solve the selection problem. Let k = N/2. Draw a table showing the running time of your program for various v
Brums [2.3K]
So here is the code in Python:

n = 0.00 #this is a float because there are some numbers that are decimals.

while n < 20: #n which is 0.00 and while it is lower than 20 if runs the code below
n = n + 1 #it will add 1 to n everything it runs the code.
k = n / 2 #it will divide whatever n is everytime by 2
print(str(n) + '/2: ') # it's printing the number it's on
print(k) # prints the answer for the n.

You can change n to add by any, make n any num instead of 0.00 and you can change the while condition from n < 20 to any other logical statement. If you want to get creative you can take 2 inputs for numbers and make one of them the starting number and other one is the ending number. Also make sure to make n a number lower than you starting point because if you set n as your starting point then it will skip it.

4 0
3 years ago
What set of code correctly initializes all elements of the array ar to the value 0, given the declaration
Veronika [31]

Answer:

The correct answer is:

C. ndx = 0;

while (ndx < 3) {

ar[ndx] = 0;

ndx++;

}

Explanation:

The declaration given is:

int ar[3];

This means the array consists of three locations and is named as ar.

We know that the indexes are used to address the locations of an array and the index starts from 0 and goes upto to 1 less than the size of the array which means the indexes of array of 3 elements will start from 0 and end at 2.

Now in the given options we are using ndx variable to run the while loop.

So the code to assign zero to all elements of array will be

ndx = 0;

while(ndx<3)

{

ar[ndx] = 0;

ndx++;

}

Hence, the correct answer is:

C. ndx = 0;

while (ndx < 3) {

ar[ndx] = 0;

ndx++;

}

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After a group sets a project schedule, members should be prepared to
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<span>make periodic adjustments on an as-needed basis.  </span>
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3 years ago
Read 2 more answers
Create a program that contains 4 methods / functions... main(), getTestScores(), calcAverage(), and displayAverage(). The main()
jeyben [28]

Answer:

import java.util.Scanner;

public class  num6{

   static int getTestScores(){

       System.out.println("Enter the Score");

       Scanner in = new Scanner(System.in);

       int score = in.nextInt();

       return score;

   }

   static double calcAverage(int score1, int score2, int score3){

       return (score1+score2+score3)/3;

   }

   static void displayAverage(double ave){

       System.out.println("The Average is "+ave);

   }

   public static void main(String[] args) {

       int num1 = getTestScores();

       int num2 = getTestScores();

       int num3 = getTestScores();

       //Calling Calculate Average

       double average = calcAverage(num1,num2,num3);

       //Calling displayAverage

       displayAverage(average);

   }

}

Explanation:

  • Using Java programming Language
  • Create the four methods
  • getTestScores() Uses the Scanner Class to receive an in variable and return it
  • calcAverage() accepts three ints as parameter calculates their average and return it
  • displayAverage() Accepts a double and prints it out with a concatenated string as message
  • In the Main Method, getTestScores is called three times to obtain three numbers from the user
  • calAverage is called and handed the three numbers
  • printAverage is called to output the calculated average
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