Answer:
def rec_dig_sum( num ):
num_list = [ digit for digit in str(num)]
total = 0
for x in num_list:
total += x
return total
def dict_of_rec_dig_sums(low, high):
mydict = dict()
for number in the range(low, high+1):
mydict[rec_dig_sum(number)] = number
return mydict
Explanation:
The python program defines two functions, "rec_dig_sum" and "dict_of_rec_dig_sums". The former accepts a number and returns the sum of the digits of the number while the latter accepts a low and high number range.
The program returns a dictionary with the recursive sum as the keys and the number count as the values.
Answer:
Technology has changed the world for the better.
Explanation:
Without technology, many of the things we take for advantage, such as, credit cards, calling people from far distances, heck even being able to call to across the world from where you are right now. Technology has revolutionized many things we use commonly on a day-to-day basis.
Answer: As the conventional etiquette, which lays out rules of ethics in social contexts, the purpose of netiquette is to help create and sustain a friendly, relaxed and productive atmosphere for online contact, as well as to avoid putting pressure on the system and creating tension between users.
Explanation:
Answer:
The solution code is written in Python 3
- digits = input("Enter 9 digits: ")
-
- multiplier = 1
- total = 0
-
- for x in digits:
- total += int(x) * multiplier
- multiplier += 1
-
- checksum = total % 11
-
- if(checksum == 10):
- print(digits + "X")
- else:
- print(digits + str(checksum))
Explanation:
Firstly, use input function to get user input for 9 digits (Line 1)
Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)
Then only apply % operator to get the remainder of total and get the checksum (Line 10)
Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)
