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3 years ago

Math problem Help please

Mathematics

2 answers:

lutik1710 [3]3 years ago

7 0

Answer:

30 65/72 yards

Step-by-step explanation:

First, change the first fraction to a mixed number. 8 x 7 = 56, plus 7 equals 63. So, the first fraction is 63/8. Next, 9 x 5 equals 45, plus 7 equals 52. So, the second fraction is 52/9. Now, you can't add fractions with different denominators, so you have to change the denominators. You can multiply the first fraction by 9 and the second fraction by 8 so they will have the same denominator of 72. 63/8 x 9 equals 567/72. 52/9 x 8 equals 416/72. 567 + 416 = 983. So, the sum of the first two fractions is 983/72. Now, convert the last fraction into a mixed number. 17 x 4 = 68, plus 1 equals 69. So, the last fraction is 69/4. Once again, the numbers need to have the same denominator, so we can multiply 69/4 by 18 to get 1242/72. Now, 983 + 1242 = 2225, so the sum of all of the fractions is 2225/72. Because this fractions is HUGE, we can change this into a mixed number. 2225/72 as a mixed number is 30 65/72. Because this fraction can't be simplified anymore, the answer would be 30 65/72. Hope this helped!

leonid [27]3 years ago

3 0

Answer:

30 65/72 yards

Step-by-step explanation:

First, make everything into improper fractions:

7 7/8 = (56 + 7)/8 = 63/8

5 7/9 = (45 + 7)/9 = 52/9

17 1/4 = (68 + 1)/4 = 69/4

Find common denominators. Note that what you do to the denominator, you must do to the numerator.

Let the common denominator be: 72:

(63/8)(9/9) = 567/72

(52/9)(8/8) = 416/72

(69/4)(18/18) = 1242/72

Combine and simplify:

(567 + 416 + 1242)/72 = 30 65/72 yds

30 65/72 yards is your answer.

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x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

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The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

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-Dominant- [34]

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