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prohojiy [21]
3 years ago
7

Y = 6x - 13 5x - 2y = 5 Using the substitution method

Mathematics
1 answer:
tankabanditka [31]3 years ago
7 0

Answer:

x=3, y=5

Step-by-step explanation:

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PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
mash [69]

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

Multiply the second equation by -1

-1 *(-3x-y+3z) =0*-1

3x +y -3z =0

Add this to the first equation

-3x -y +z=6

3x +y -3z =0

----------------------

0 + 0 + -2z = 6

Divide by -2

-2z/-2 = 6/-2

z = 6/-2

z=-3


Take the third equation to find x

x-3z=3

x-3(-3) = 3

x+9=3

Subtract 9 from each side

x+9-9 =3-9

x=-6

Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

-9+y =0

Add 9 to each side

-9+9+y = 0+9

y=9

(-6,9,-3)

3 0
3 years ago
Read 2 more answers
Ben and Tom each take a driving test.
GaryK [48]

Answer:

(b)0.56

(c)0.38

Step-by-step explanation:

(a)The tree diagram is attached.

P(Ben Fails)=1-0.8=0.2

P(Tom Fails)=1-0.7=0.3

(b)Probability that  both will pass their driving test.

P(both will pass)=0.8 X 0.7 =0.56

(c)Probability that  only one of them will pass their  driving test.

P(Tom Bass, Ben Fails OR Ben Pass, Tom Fails)

=(0.7 X 0.2)+(0.8 X 0.3)

=0.14+0.24

=0.38

3 0
3 years ago
Rewrite terms that are subtracted as addition of the opposite. g2 + (–4g4) + 5g + 9 + (–3g3) + 3g2 + (–6) Group like terms. Comb
Vilka [71]

Answer:

-4g^4 -3g^3 + 4g^2 +5g +3

Step-by-step explanation:

g^2 + -4g^4 +5g +9 -3g^3 + 3g^2 -6

-4g^4 -3g^3 + 4g^2 +5g +3

3 0
3 years ago
For the data shown in the scatter plot, which is the best estimate of r? -0.95, -0.55, 0.55, 0.95
Liula [17]
From the data shown in the scater plots, the points are scattered apart which means that r is not close to 1.

Also the data points increase to the right which means that r is positive.

Therefore, the estimate for r in the data shown in the scatter plot is 0.55
6 0
3 years ago
Can someone help me with this????
AlladinOne [14]
The answer is 1.
Rise over run :)
8 0
3 years ago
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