The rate constant for the nuclide according to first-order kinetics is 0.3863 per day.
Nuclear Decay in First-Order Kinetics:
m(t) = Me∧(-αt)
where m(t) = mass of nuclide after decay at time t;
M = mass of nuclide before decay;
α = rate constant of decay;
t = time for the decay;
<h3>What is first-order kinetics?</h3>
When a fixed percentage of the drug is excreted per unit of time, this is known as first-order kinetics.
For example, The amount of drug in the body has a direct relationship to the rate of removal. The amount of medication eliminated per unit of time increases with concentration. The medication concentration decreases by 50% for each half-life.
Now,
m(t) = Me∧(-αt)
⇒e∧(αt) = M/m(t)
applying ln on both sides;
αt = ln(m/m(t))
α = (ln(m/m(t))/t)
here t= 3.4 days, M = 45 grams, m(t) = 12.1 grams;
dropping these values in the above equation we get,
α = 0.3863 per day;
The rate constant for the nuclide according to first-order kinetics is 0.3863 per day.
To refer more about First Order Kinetics visit:
brainly.com/question/14977977
#SPJ4
